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The differential diagnosis of hypernatraemia in children, with ...

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<strong>The</strong> Diagnosis <strong>of</strong> Salt Poison<strong>in</strong>g Lead<strong>in</strong>g to Hypematraemia <strong>in</strong> Children – September 2009<br />

figures from the paper show clearly that there is no significant relationship between the<br />

plasma sodium concentration and the ratio <strong>of</strong> total body water to exchangeable sodium<br />

(found ma<strong>in</strong>ly <strong>in</strong> the extracellular fluid) (Fig 5), but a very good relationship between<br />

the plasma sodium concentration and the ratio <strong>of</strong> total body water to the sum <strong>of</strong> total<br />

exchangeable sodium (extracellular fluid) and potassium (<strong>in</strong>tracellular fluid) (Fig 7):<br />

<strong>The</strong>refore, although adm<strong>in</strong>istered sodium does not enter cells, any prediction <strong>of</strong> rise <strong>in</strong><br />

serum sodium follow<strong>in</strong>g excessive sodium adm<strong>in</strong>istration should be calculated on the<br />

assumption that it is distributed throughout the total body water. 27<br />

One gram <strong>of</strong> salt conta<strong>in</strong>s 17 mmol each <strong>of</strong> sodium and chloride. Total body water amounts<br />

to approximately 65% <strong>of</strong> total body weight <strong>in</strong> <strong>children</strong>. 281 <strong>The</strong> extracellular space is<br />

approximately 25% <strong>of</strong> total body weight.<br />

So tak<strong>in</strong>g an example, how much salt would raise the sodium from 140 to 180 mmol/l?<br />

Firstly, assume rapid assimilation (e.g. IV <strong>in</strong>fusion) and <strong>with</strong> no correction for any <strong>of</strong> the<br />

adm<strong>in</strong>istered sodium that might have been excreted by the time at which the elevated<br />

concentration was measured. This would require only 10 mmol sodium (equivalent to<br />

0.59 grams <strong>of</strong> salt)/kilogram body weight [or 25% <strong>of</strong> 40 mmol/L] if the extracellular fluid<br />

space is taken as the volume <strong>of</strong> distribution. However, it would require 26 mmol sodium<br />

(equivalent to 1.53 grams <strong>of</strong> salt)/kilogram body weight [or 65% <strong>of</strong> 40 mmol/L], us<strong>in</strong>g<br />

total body water, the correct procedure. Roughly speak<strong>in</strong>g this is the difference between 1<br />

teaspoon and 3 teaspoons <strong>of</strong> salt for a 10 kilogram child.<br />

73

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