PHYS08200605006 D.K. Hazra - Homi Bhabha National Institute
PHYS08200605006 D.K. Hazra - Homi Bhabha National Institute
PHYS08200605006 D.K. Hazra - Homi Bhabha National Institute
Create successful ePaper yourself
Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.
CHAPTER 5. THE SCALAR BI-SPECTRUM DURING PREHEATING<br />
terms during preheating can be written as<br />
[ (<br />
G 1 (k 1 ,k 2 ,k 3 )+G 3 (k 1 ,k 2 ,k 3 ) = 2iM 2 1− k 1 ·k 2<br />
− k )<br />
1 ·k 3<br />
|A<br />
Pl<br />
k2<br />
2 k3<br />
2 k1 | 2<br />
× ( )<br />
A k2<br />
¯B∗ k2<br />
A k3<br />
¯B∗ k3<br />
−A ∗ k<br />
¯Bk2 2<br />
A ∗ k<br />
¯Bk3<br />
] 3<br />
+two permutations<br />
I 13 (η f ,η e ), (5.31)<br />
where the quantity I 13 (η f ,η e ) represents the integral<br />
I 13 (η f ,η e ) =<br />
∫ ηf<br />
This integral can be trivially carried out during preheating to yield<br />
η e<br />
dη<br />
a2. (5.32)<br />
I 13 (η f ,η e ) = t e<br />
a 3 e<br />
[<br />
1−e<br />
−3(N f −N e)/2 ] . (5.33)<br />
Since the second term in this expression for I 13 (η f ,η e ) dies quickly with growing N f , the<br />
corresponding contribution to the bi-spectrum proves to be negligible.<br />
The contributions due to the fifth and the sixth terms during preheating can be arrived<br />
at in a similar fashion. We obtain that<br />
{[<br />
G 5 (k 1 ,k 2 ,k 3 )+G 6 (k 1 ,k 2 ,k 3 ) = iM2 Pl k1 ·k 2<br />
+ k 1 ·k 3<br />
+ k2 1 (k ]<br />
2 ·k 3 )<br />
|A<br />
2 k2<br />
2 k3<br />
2 k2k 2 3<br />
2 k1 | 2<br />
( )<br />
Ak2 ¯B∗ k2<br />
A k3<br />
¯B∗ k3<br />
− A ∗ ¯Bk2 k 2<br />
A ∗ ¯Bk3 k 3<br />
}<br />
+ two permutations I 56 (η f ,η e ), (5.34)<br />
with I 56 (η f ,η e ) denoting the integral<br />
I 56 (η f ,η e ) =<br />
∫ ηf<br />
η e<br />
dη<br />
a 2 ǫ 1. (5.35)<br />
This integral too can be evaluated rather easily to arrive at the following expression:<br />
I 56 (η f ,η e ) = 3t e<br />
a 3 e<br />
(<br />
cos 2 (mt e +∆)−e −3(N f−N e)/2 cos 2[ mt e e 3(N f−N e)/2 +∆ ]<br />
+mt e cos(2∆) { Si(2mt e )−Si [ 2mt e e 3(N f−N e)/2 ]}<br />
+mt e sin(2∆) { Ci(2mt e )−Ci [ 2mt e e 3(N f−N e)/2 ]}) , (5.36)<br />
102