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Chapter 12 Sequences; Induction; the Binomial Theorem

Chapter 12 Sequences; Induction; the Binomial Theorem

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<strong>Chapter</strong> <strong>12</strong>: <strong>Sequences</strong>; <strong>Induction</strong>; <strong>the</strong> <strong>Binomial</strong> <strong>Theorem</strong><br />

93. 1, 1, 2, 3, 5, 8, 13<br />

This is <strong>the</strong> Fibonacci sequence.<br />

94. a. u1 = 1, u2 = 1, u3 = 2, u4 = 3, u5<br />

= 5,<br />

u6 = 8, u7 = 13, u8 = 21, u9 = 34, u10<br />

= 55,<br />

u = 89<br />

b.<br />

11<br />

u2 1 u3<br />

2 u4<br />

3<br />

= = 1, = = 2, = = 1.5,<br />

u1 1 u2 1 u3<br />

2<br />

u5 5 u6<br />

8<br />

= ≈ 1.67, = = 1.6,<br />

u4 3 u5<br />

5<br />

u7 13 u8<br />

21<br />

= = 1.625, = ≈1.615,<br />

u6 8 u7<br />

13<br />

u9 34 u10<br />

55<br />

= ≈ 1.619, = ≈1.618,<br />

u8 21 u9<br />

34<br />

u11<br />

89<br />

= ≈1.618<br />

u 55<br />

10<br />

⎛<br />

1+<br />

5⎞<br />

c. 1.618 ⎜The exact value is ⎟<br />

⎝<br />

2 ⎠<br />

u1 1 u2<br />

1 u3<br />

2<br />

d. = = 1, = = 0.5, = ≈ 0.667,<br />

u2 1 u3 2 u4<br />

3<br />

u4<br />

3 u5<br />

5<br />

= = 0.6, = = 0.625,<br />

u5 5 u6<br />

8<br />

u6 8 u7<br />

13<br />

= ≈ 0.615, = ≈0.619,<br />

u7 13 u8<br />

21<br />

u8 21 u9<br />

34<br />

= ≈ 0.618, = ≈0.618,<br />

u9 34 u10<br />

55<br />

u10<br />

55<br />

= ≈0.618<br />

u 89<br />

11<br />

1.3<br />

c. f ( ) e<br />

1.3 = ≈ 3.669296668<br />

d. It will take n = <strong>12</strong> to approximate<br />

f<br />

1.3<br />

( 1.3) e<br />

96. a. ( 2.4)<br />

= correct to 8 decimal places.<br />

3<br />

( 2.4)<br />

∑<br />

2.4<br />

f e − −<br />

− = ≈<br />

b. ( 2.4)<br />

k = 0<br />

k!<br />

( −2.4) ( −2.4) ( −2.4) ( −2.4)<br />

+ + +<br />

0 1 2 3<br />

=<br />

0! 1! 2! 3!<br />

=−0.824<br />

2.4 ( 2.4)<br />

f e − −<br />

− = ≈<br />

2.4<br />

c. f ( ) e −<br />

6<br />

∑<br />

k = 0<br />

k!<br />

( −2.4) ( −2.4) ( −2.4)<br />

= + + ... +<br />

0 1 6<br />

0! 1! 6!<br />

= 0.1602688<br />

− 2.4 = ≈ 0.0907179533<br />

k<br />

k<br />

e. 0.618<br />

⎛<br />

2 ⎞<br />

⎜The exact value is ⎟<br />

⎝<br />

1 + 5 ⎠<br />

d. It will take n = 17 to approximate<br />

f<br />

2.4<br />

( 2.4) e −<br />

− = correct to 8 decimal places.<br />

95. a. f ( 1.3)<br />

b. f ( 1.3)<br />

4<br />

k<br />

1.3 1.3<br />

∑ k!<br />

k = 0<br />

= e ≈<br />

0 1 4<br />

1.3 1.3 1.3<br />

= + + ... +<br />

0! 1! 4!<br />

≈ 3.630170833<br />

7<br />

k<br />

1.3 1.3<br />

∑ k!<br />

k = 0<br />

= e ≈<br />

0 1 7<br />

1.3 1.3 1.3<br />

= + + ... +<br />

0! 1! 7!<br />

≈ 3.669060828<br />

<strong>12</strong>44<br />

© 2009 Pearson Education, Inc., Upper Saddle River, NJ. All rights reserved. This material is protected under all copyright laws as <strong>the</strong>y currently<br />

exist. No portion of this material may be reproduced, in any form or by any means, without permission in writing from <strong>the</strong> publisher.

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