Chapter 12 Sequences; Induction; the Binomial Theorem
Chapter 12 Sequences; Induction; the Binomial Theorem
Chapter 12 Sequences; Induction; the Binomial Theorem
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<strong>Chapter</strong> <strong>12</strong>: <strong>Sequences</strong>; <strong>Induction</strong>; <strong>the</strong> <strong>Binomial</strong> <strong>Theorem</strong><br />
93. 1, 1, 2, 3, 5, 8, 13<br />
This is <strong>the</strong> Fibonacci sequence.<br />
94. a. u1 = 1, u2 = 1, u3 = 2, u4 = 3, u5<br />
= 5,<br />
u6 = 8, u7 = 13, u8 = 21, u9 = 34, u10<br />
= 55,<br />
u = 89<br />
b.<br />
11<br />
u2 1 u3<br />
2 u4<br />
3<br />
= = 1, = = 2, = = 1.5,<br />
u1 1 u2 1 u3<br />
2<br />
u5 5 u6<br />
8<br />
= ≈ 1.67, = = 1.6,<br />
u4 3 u5<br />
5<br />
u7 13 u8<br />
21<br />
= = 1.625, = ≈1.615,<br />
u6 8 u7<br />
13<br />
u9 34 u10<br />
55<br />
= ≈ 1.619, = ≈1.618,<br />
u8 21 u9<br />
34<br />
u11<br />
89<br />
= ≈1.618<br />
u 55<br />
10<br />
⎛<br />
1+<br />
5⎞<br />
c. 1.618 ⎜The exact value is ⎟<br />
⎝<br />
2 ⎠<br />
u1 1 u2<br />
1 u3<br />
2<br />
d. = = 1, = = 0.5, = ≈ 0.667,<br />
u2 1 u3 2 u4<br />
3<br />
u4<br />
3 u5<br />
5<br />
= = 0.6, = = 0.625,<br />
u5 5 u6<br />
8<br />
u6 8 u7<br />
13<br />
= ≈ 0.615, = ≈0.619,<br />
u7 13 u8<br />
21<br />
u8 21 u9<br />
34<br />
= ≈ 0.618, = ≈0.618,<br />
u9 34 u10<br />
55<br />
u10<br />
55<br />
= ≈0.618<br />
u 89<br />
11<br />
1.3<br />
c. f ( ) e<br />
1.3 = ≈ 3.669296668<br />
d. It will take n = <strong>12</strong> to approximate<br />
f<br />
1.3<br />
( 1.3) e<br />
96. a. ( 2.4)<br />
= correct to 8 decimal places.<br />
3<br />
( 2.4)<br />
∑<br />
2.4<br />
f e − −<br />
− = ≈<br />
b. ( 2.4)<br />
k = 0<br />
k!<br />
( −2.4) ( −2.4) ( −2.4) ( −2.4)<br />
+ + +<br />
0 1 2 3<br />
=<br />
0! 1! 2! 3!<br />
=−0.824<br />
2.4 ( 2.4)<br />
f e − −<br />
− = ≈<br />
2.4<br />
c. f ( ) e −<br />
6<br />
∑<br />
k = 0<br />
k!<br />
( −2.4) ( −2.4) ( −2.4)<br />
= + + ... +<br />
0 1 6<br />
0! 1! 6!<br />
= 0.1602688<br />
− 2.4 = ≈ 0.0907179533<br />
k<br />
k<br />
e. 0.618<br />
⎛<br />
2 ⎞<br />
⎜The exact value is ⎟<br />
⎝<br />
1 + 5 ⎠<br />
d. It will take n = 17 to approximate<br />
f<br />
2.4<br />
( 2.4) e −<br />
− = correct to 8 decimal places.<br />
95. a. f ( 1.3)<br />
b. f ( 1.3)<br />
4<br />
k<br />
1.3 1.3<br />
∑ k!<br />
k = 0<br />
= e ≈<br />
0 1 4<br />
1.3 1.3 1.3<br />
= + + ... +<br />
0! 1! 4!<br />
≈ 3.630170833<br />
7<br />
k<br />
1.3 1.3<br />
∑ k!<br />
k = 0<br />
= e ≈<br />
0 1 7<br />
1.3 1.3 1.3<br />
= + + ... +<br />
0! 1! 7!<br />
≈ 3.669060828<br />
<strong>12</strong>44<br />
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