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Chapter 12 Sequences; Induction; the Binomial Theorem

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<strong>Chapter</strong> <strong>12</strong> Review Exercises<br />

50.<br />

8<br />

<strong>12</strong>! = 479,001,600 = 4.790016×<br />

10<br />

18<br />

20! ≈ 2.432902008×<br />

10<br />

25<br />

25! ≈ 1.551<strong>12</strong>1004×<br />

10<br />

⎛<strong>12</strong> ⎞ ⎛ 1 ⎞<br />

<strong>12</strong>! ≈ 2⋅<strong>12</strong>π ⎜ ⎟ ⎜1+<br />

⎟<br />

⎝ e ⎠ ⎝ <strong>12</strong> ⋅ <strong>12</strong> − 1 ⎠<br />

≈ 479,013,972.4<br />

⎛20 ⎞ ⎛ 1 ⎞<br />

20! ≈ 2⋅20π ⎜ ⎟ ⎜1+<br />

⎟<br />

⎝ e ⎠ ⎝ <strong>12</strong> ⋅ 20 − 1 ⎠<br />

18<br />

≈ 2.43292403×<br />

10<br />

⎛25 ⎞ ⎛ 1 ⎞<br />

25! ≈ 2⋅25π ⎜ ⎟ ⎜1+<br />

⎟<br />

⎝ e ⎠ ⎝ <strong>12</strong> ⋅ 25 − 1 ⎠<br />

25<br />

≈ 1.551<strong>12</strong>9917×<br />

10<br />

<strong>Chapter</strong> <strong>12</strong> Review Exercises<br />

1.<br />

2.<br />

3.<br />

4.<br />

<strong>12</strong><br />

20<br />

25<br />

11+ 3 4 2 2+<br />

3 5<br />

a1 = ( − 1) =− , a2<br />

= ( − 1) = ,<br />

1+ 2 3 2+<br />

2 4<br />

3 3+ 3 6 4 4+<br />

3 7<br />

a3 = ( − 1) =− , a4<br />

= ( − 1) = ,<br />

3+ 2 5 4+<br />

2 6<br />

5 5+<br />

3 8<br />

a5<br />

= ( − 1) =− 5 + 2 7<br />

11 +<br />

b1<br />

= ( −1) (2 ⋅ 1+ 3) = 5,<br />

2+<br />

1<br />

b2<br />

= ( −1) (2⋅ 2+ 3) =−7,<br />

3+<br />

1<br />

b3<br />

= ( −1) (2⋅ 3+ 3) = 9,<br />

4+<br />

1<br />

b4<br />

= ( −1) (2⋅ 4+ 3) =−11,<br />

5+<br />

1<br />

b = ( −1) (2⋅ 5+ 3) = 13<br />

5<br />

1 2 3<br />

1 2 2 2 3 2<br />

2 2 2 4 2 8<br />

c = = = 2, c = = = 1, c = = ,<br />

1 1 2 4 3 9<br />

4 5<br />

2 16 2 32<br />

c4 = = = 1, c<br />

2 5 = =<br />

2<br />

4 16 5 25<br />

1 2 3 4 5<br />

1 = e = , 2 = e , 3 = e , e 4 = ,<br />

e<br />

5 =<br />

d e d d d d<br />

1 2 3 4 5<br />

2 2 4<br />

a = 3, a = ⋅ 3 = 2, a = ⋅ 2 = ,<br />

3 3 3<br />

2 4 8 2 8 16<br />

a4 = ⋅ = , a5<br />

= ⋅ =<br />

3 3 9 3 9 27<br />

5. 1 2 3<br />

1 1 1<br />

= 4, =− ⋅ 4 =− 1, =− ⋅− 1 = ,<br />

4 4 4<br />

1 1 1 1 1 1<br />

a4 =− ⋅ =− , a5<br />

=− ⋅− =<br />

4 4 16 4 16 64<br />

6. a1 a2 a3<br />

a = 2, a = 2 − 2 = 0, a = 2 − 0 = 2,<br />

7. 1 2 3<br />

a<br />

= 2− 2= 0, a = 2− 0=<br />

2<br />

4 5<br />

8. a1 a2 a3<br />

9.<br />

a<br />

= − 3, = 4 + ( − 3) = 1, = 4 + 1 = 5,<br />

= 4+ 5= 9, a = 4+ 9=<br />

13<br />

4 5<br />

4<br />

∑<br />

k = 1<br />

(4k<br />

+ 2)<br />

( 4 1 2) ( 4 2 2) ( 4 3 2) ( 4 4 2)<br />

( 6) ( 10) ( 14) ( 18)<br />

= ⋅ + + ⋅ + + ⋅ + + ⋅ +<br />

= + + +<br />

= 48<br />

3<br />

2 2 2 2<br />

10. ∑ (3 − k ) = ( 3 − 1 ) + ( 3 − 2 ) + ( 3 −3<br />

)<br />

k = 1<br />

( 2) ( 1) ( 6)<br />

= + − + −<br />

=−5<br />

1 1 1 1 k + 1 ⎛1⎞<br />

− + − +⋅⋅⋅+ = − ⎜ ⎟<br />

2 3 4 13<br />

⎝k<br />

⎠<br />

11. 1 ∑ ( 1)<br />

13<br />

k = 1<br />

2 3 4 n+ 1 n 1<br />

2 2 2 2 ⎛<br />

k+<br />

2 ⎞<br />

<strong>12</strong>. 2 + + + +⋅⋅⋅+ =<br />

2 3<br />

n ∑<br />

k<br />

3 3 3 3 ⎜<br />

k = 0 3 ⎟<br />

⎝ ⎠<br />

n+<br />

1⎛<br />

k<br />

2 ⎞<br />

= ∑<br />

⎜ k −1<br />

k = 1 3 ⎟<br />

⎝ ⎠<br />

13. { a } { n 5}<br />

n<br />

= + Arithmetic<br />

d = ( n+ 1+ 5) − ( n+ 5) = n+ 6−n− 5=<br />

1<br />

n<br />

n<br />

Sn<br />

= [ 6+ n+ 5 ] = ( n+<br />

11)<br />

2 2<br />

14. { b } { 4n<br />

3}<br />

n<br />

= + Arithmetic<br />

d = (4( n+ 1) + 3) − (4n+<br />

3)<br />

= 4n+ 4+ 3−4n− 3=<br />

4<br />

n<br />

Sn<br />

= + +<br />

2<br />

n<br />

= (4n<br />

+ 10)<br />

2<br />

= n +<br />

[ 7 4n<br />

3]<br />

( 2n<br />

5)<br />

<strong>12</strong>73<br />

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