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Chapter 12 Sequences; Induction; the Binomial Theorem

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<strong>Chapter</strong> <strong>12</strong>: <strong>Sequences</strong>; <strong>Induction</strong>; <strong>the</strong> <strong>Binomial</strong> <strong>Theorem</strong><br />

(c) Enter <strong>the</strong> recursive formula in Y= and<br />

create <strong>the</strong> table:<br />

b.<br />

⎛ 0.065 ⎞<br />

⎜1 + ⎟(<strong>12</strong>0,000) −758.48<br />

= $119,891.52<br />

⎝ <strong>12</strong> ⎠<br />

c. Enter <strong>the</strong> recursive formula in Y= and create<br />

<strong>the</strong> table:<br />

(d) Scroll through <strong>the</strong> table:<br />

d. Scroll through <strong>the</strong> table:<br />

After 37 payments have been made, <strong>the</strong><br />

balance is below $140,000. The<br />

balance is $139,894.<br />

(e) Scroll through <strong>the</strong> table:<br />

After <strong>12</strong>9 payments have been made, <strong>the</strong><br />

balance is below $100,000. The balance is<br />

about $99,824.<br />

e. Scroll through <strong>the</strong> table:<br />

The loan will be paid off at <strong>the</strong> end of<br />

279 months or 23 years and 3 months.<br />

Total amount paid = (278)($999.33) +<br />

353.69(1.005) = $278,169.20<br />

(f) The total interest expense is <strong>the</strong><br />

difference of <strong>the</strong> total of <strong>the</strong> payments<br />

and <strong>the</strong> original loan:<br />

278,169.20 − 150,000 = $<strong>12</strong>8,169.20<br />

h. Yes, if <strong>the</strong>y can afford <strong>the</strong> additional<br />

monthly payment. They would save<br />

$44,586.07 in interest payments by paying<br />

<strong>the</strong> loan off sooner.<br />

90. a. Since <strong>the</strong> interest rate is 6.5% per annum<br />

compounded at a rate of (6.5/<strong>12</strong>)% each<br />

month. Defining a recursive sequence, we<br />

have:<br />

a0<br />

= <strong>12</strong>0,000,<br />

⎛ 0.065 ⎞<br />

an<br />

= ⎜1+ ⎟an<br />

− 1 −758.48<br />

⎝ <strong>12</strong> ⎠<br />

The loan will be paid in <strong>the</strong> 360th month i.e.<br />

after 30 years.<br />

Total amount paid = (359)(758.48) +<br />

756.19(1+0.065/<strong>12</strong>) = $273,054.60.<br />

f. The total interest expense is <strong>the</strong> difference<br />

of <strong>the</strong> total of <strong>the</strong> payments and <strong>the</strong> original<br />

loan: 273,054.60 − <strong>12</strong>0,000 = $153,054.60<br />

g. (a) Since <strong>the</strong> interest rate is 6.5% per<br />

annum compounded monthly, this is<br />

equivalent to a rate of (6.5/<strong>12</strong>)% each<br />

month. Defining a recursive sequence,<br />

we have:<br />

a0<br />

= <strong>12</strong>0,000,<br />

⎛ 0.065 ⎞<br />

an<br />

= ⎜1+ ⎟an<br />

− 1 −858.48<br />

⎝ <strong>12</strong> ⎠<br />

<strong>12</strong>42<br />

© 2009 Pearson Education, Inc., Upper Saddle River, NJ. All rights reserved. This material is protected under all copyright laws as <strong>the</strong>y currently<br />

exist. No portion of this material may be reproduced, in any form or by any means, without permission in writing from <strong>the</strong> publisher.

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