Chapter 12 Sequences; Induction; the Binomial Theorem
Chapter 12 Sequences; Induction; the Binomial Theorem
Chapter 12 Sequences; Induction; the Binomial Theorem
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Section <strong>12</strong>.3: Geometric <strong>Sequences</strong>; Geometric Series<br />
21.<br />
22.<br />
a<br />
a<br />
a<br />
a<br />
5<br />
n<br />
5<br />
n<br />
5−1 4<br />
⎛1⎞ ⎛1⎞<br />
= 0⋅ ⎜ ⎟ = 0⋅ ⎜ ⎟ = 0<br />
⎝2⎠ ⎝2⎠<br />
n−1<br />
⎛1<br />
⎞<br />
= 0⋅ ⎜ ⎟ = 0<br />
⎝2<br />
⎠<br />
5−1 4<br />
⎛ 1⎞ ⎛ 1⎞<br />
1<br />
= 1⋅⎜− ⎟ = 1⋅⎜− ⎟ =<br />
⎝ 3⎠ ⎝ 3⎠<br />
81<br />
n−1 n−1<br />
⎛ 1⎞ ⎛ 1⎞<br />
= 1⋅⎜− ⎟ = ⎜−<br />
⎟<br />
⎝ 3⎠ ⎝ 3⎠<br />
−<br />
23. a5<br />
( ) ( )<br />
n−1<br />
n<br />
an<br />
= 2⋅ ( 2) = ( 2)<br />
24.<br />
a<br />
a<br />
5<br />
n<br />
5 1 4<br />
= 2⋅ 2 = 2⋅ 2 = 2⋅ 4=<br />
4 2<br />
5−1 4<br />
⎛1⎞ ⎛1⎞<br />
= 0⋅ ⎜ ⎟ = 0⋅ ⎜ ⎟ = 0<br />
⎝π⎠ ⎝π⎠<br />
n−1<br />
⎛1<br />
⎞<br />
= 0⋅ ⎜ ⎟ = 0<br />
⎝π<br />
⎠<br />
1<br />
25. a1<br />
= 1, r = , n = 7<br />
2<br />
a<br />
7<br />
7−1 6<br />
⎛1⎞ ⎛1⎞<br />
1<br />
= 1⋅ ⎜ ⎟ = ⎜ ⎟ =<br />
⎝ 2 ⎠ ⎝ 2 ⎠ 64<br />
26. a1<br />
= 1, r = 3, n = 8<br />
27.<br />
a<br />
8<br />
1<br />
9<br />
8−1 7<br />
= 1⋅ 3 = 3 = 2187<br />
a = 1, r =− 1, n = 9<br />
a<br />
−<br />
( ) ( )<br />
9 1 8<br />
= 1⋅ − 1 = − 1 = 1<br />
10<br />
n<br />
32. a 1 = 5 , r = = 2 , an<br />
= a1<br />
⋅ r −<br />
5<br />
1<br />
52 n −<br />
= ⋅<br />
a n<br />
1 1<br />
n<br />
33. a 1 = − 3 , r = =− , an<br />
= a1<br />
⋅ r −<br />
−3 3<br />
n−1 n−2<br />
⎛ 1⎞ ⎛ 1⎞<br />
a n =−3⎜− ⎟ = ⎜−<br />
⎟<br />
⎝ 3⎠ ⎝ 3⎠<br />
1<br />
n<br />
34. a 1 = 4 , r = , an<br />
= a1<br />
⋅ r −<br />
4<br />
n−1 n−2<br />
⎛1⎞ ⎛1⎞<br />
a n = 4⎜ ⎟ = ⎜ ⎟<br />
⎝ 4 ⎠ ⎝ 4 ⎠<br />
35.<br />
36.<br />
n 1<br />
an<br />
= a1<br />
⋅ r −<br />
243 = a ⋅ −3<br />
1<br />
1<br />
( )<br />
5<br />
( )<br />
243 = a1<br />
−3<br />
243 =−243a<br />
− 1 = a<br />
Therefore,<br />
a = a ⋅ r −<br />
1<br />
a n<br />
n 1<br />
n 1<br />
2−1<br />
⎛1<br />
⎞<br />
7 = a1<br />
⎜ ⎟<br />
⎝3<br />
⎠<br />
1<br />
7 = a1<br />
3<br />
21 = a<br />
1<br />
Therefore,<br />
a n<br />
6−1<br />
=−− ( 3) n<br />
−1<br />
n<br />
⎛1<br />
⎞<br />
= 21⎜ ⎟<br />
⎝ 3 ⎠<br />
−1<br />
.<br />
1<br />
1<br />
1<br />
28.<br />
29.<br />
30.<br />
a =− 1, r =− 2, n=<br />
10<br />
a<br />
1<br />
10<br />
1<br />
8<br />
−<br />
( ) ( )<br />
10 1 9<br />
=−1⋅ − 2 = −1⋅ − 2 =−1( − 5<strong>12</strong>) = 5<strong>12</strong><br />
a = 0.4, r = 0.1, n=<br />
8<br />
a<br />
1<br />
7<br />
−<br />
( ) ( )<br />
8 1 7<br />
= 0.4⋅ 0.1 = 0.4 0.1 = 0.00000004<br />
a = 0.1, r = 10, n=<br />
7<br />
a<br />
7−1<br />
( )<br />
= 0.1⋅ 10 = 0.1 10 = 100,000<br />
14<br />
n<br />
31. a 1 = 7 , r = = 2 , an<br />
= a1<br />
⋅ r −<br />
7<br />
1<br />
7 2 n −<br />
= ⋅<br />
a n<br />
6<br />
1<br />
37.<br />
2 1<br />
4−1 3<br />
a4 a1⋅<br />
r r<br />
= = = r<br />
2−1<br />
a a ⋅ r r<br />
2 1575<br />
r = = 225<br />
7<br />
r = 225 = 15<br />
a = a ⋅r<br />
n<br />
1<br />
1<br />
1<br />
n−1<br />
7 = a ⋅15<br />
7 = 15a<br />
7<br />
a1<br />
=<br />
15<br />
Therefore,<br />
2−1<br />
a n<br />
2<br />
7 15<br />
n−1 7 15<br />
n−2<br />
= ⋅ = ⋅ .<br />
15<br />
<strong>12</strong>55<br />
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