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Constructions of harmonic maps between Hadamard manifolds

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1.2. GLOBAL PROPERTIES OF SOLUTIONS 33<br />

for any nonnegative integers m and n. As a consequence, we have<br />

{f 1 (t) p f 2 (t) q ṙ(t)} 2 ≤{f 1 (t 1 ) p f 2 (t 1 ) q ṙ(t 1 )} 2<br />

Letting t 1 tend to 0, we have<br />

+ µ 2 {f 1 (t) 2p−2 f 2 (t) 2q h 1 (r(t)) 2 − f 1 (t 1 ) 2p−2 f 2 (t 1 ) 2q h 1 (r(t 1 )) 2 }<br />

+ ν 2 {f 1 (t) 2p f 2 (t) 2q−2 h 2 (r(t)) 2 − f 1 (t 1 ) 2p f 2 (t 1 ) 2q−2 h 2 (r(t 1 )) 2 }.<br />

{f 1 (t) p f 2 (t) q ṙ(t)} 2 ≤ µ 2 f 1 (t) 2p−2 f 2 (t) 2q h 1 (r(t)) 2 + ν 2 f 1 (t) 2p f 2 (t) 2q−2 h 2 (r(t)) 2 .<br />

Dividing both sides by f 1 (t) 2p f 2 (t) 2q , we obtain the conclusion.<br />

Using this lemma, we present a sufficient condition for the existence <strong>of</strong> a global solution<br />

in terms <strong>of</strong> a relation <strong>between</strong> t 0 and r 0 .<br />

If r(t) = 0 for some t>0, then r(t) ≡ 0 by Corollary 1.1.3. Hence it is a global solution.<br />

In the sequel <strong>of</strong> this section we assume that r(t) > 0 for all t>0.<br />

Let<br />

⎧<br />

⎪⎨ max{h 1 (r),h 2 (r)} (ν >0),<br />

h(r) =<br />

⎪⎩ h 1 (r) (ν =0).<br />

Since ṙ(t) > 0, we have<br />

{<br />

ṙ(t) 1<br />

h(r(t)) ≤ γ f 1 (t) + 1 }<br />

,<br />

f 2 (t)<br />

where γ = max{µ, ν}. Integrating both sides from t 0 to t(∈ [t 0 ,T]), we obtain<br />

∫ r(t) ∫<br />

ds<br />

t<br />

{ 1<br />

(1.2.3)<br />

h(s) ≤ γ t 0<br />

f 1 (τ) + 1 }<br />

dτ.<br />

f 2 (τ)<br />

r 0<br />

Theorem 1.2.3. If r 0 satisfies<br />

∫ ∞ ∫<br />

dr<br />

∞<br />

{ 1<br />

(1.2.4)<br />

r 0<br />

h(r) >γ t 0<br />

f 1 (τ) + 1 }<br />

dτ,<br />

f 2 (τ)<br />

then the solution to the equation (1.1.1) with the boundary condition (1.1.2) exists globally<br />

and is bounded.

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