Chem 55 Exam 2 Solutions
Chem 55 Exam 2 Solutions
Chem 55 Exam 2 Solutions
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CHEM <strong>55</strong> Fall 2007 <strong>Exam</strong> 1 Copy # 1<br />
Name: Au,Hai Nguyen<br />
Values of Student's t<br />
% confidence interval<br />
°freedom 50 80 95 99<br />
1 1.00 3.08 12.71 63.66<br />
2 0.82 1.89 4.30 9.92<br />
3 0.76 1.64 3.18 5.84<br />
4 0.74 1.53 2.78 4.60<br />
5 0.73 1.48 2.57 4.03<br />
6 0.72 1.44 2.45 3.71<br />
7 0.71 1.41 2.36 3.50<br />
8 0.71 1.40 2.31 3.36<br />
9 0.70 1.38 2.26 3.25<br />
10 0.70 1.37 2.23 3.17<br />
20 0.69 1.33 2.09 2.85<br />
50 0.68 1.30 2.01 2.68<br />
100 0.68 1.29 1.98 2.63<br />
∞ 0.67 1.28 1.96 2.58<br />
Values of Q for rejection of data:<br />
Q<br />
90% confidence<br />
Number of<br />
Observations<br />
0.76 4<br />
0.64 5<br />
0.56 6<br />
0.51 7<br />
0.47 8<br />
0.44 9<br />
0.41 10<br />
Average, Sample standard deviation<br />
and confidence interval formulae:<br />
x =<br />
n<br />
∑<br />
i=<br />
1<br />
n<br />
n<br />
x<br />
∑<br />
( xi<br />
− x)<br />
i=<br />
1<br />
s =<br />
n −1<br />
CI = x ±<br />
ts<br />
n<br />
( x − μ)<br />
t =<br />
s<br />
i<br />
n<br />
2<br />
Error propagation formulae:<br />
for : y = x1<br />
+ x2<br />
for : y = x1⋅<br />
x2<br />
for : y = log( x)<br />
for : y = 10<br />
for : y = ln( x)<br />
for : y = e<br />
for : y = x<br />
x<br />
a<br />
x<br />
e<br />
e<br />
y<br />
y<br />
% e<br />
y<br />
e<br />
y<br />
% e<br />
y<br />
=<br />
=<br />
ex<br />
ey<br />
=<br />
x<br />
= y ⋅e<br />
x<br />
e<br />
2<br />
x1<br />
= a ⋅%<br />
e<br />
% e<br />
x<br />
+ e<br />
2<br />
x1<br />
ex<br />
ey<br />
= 0.434<br />
x<br />
= 2.303⋅<br />
y ⋅e<br />
x<br />
2<br />
x2<br />
+ % e<br />
2<br />
x2