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Testing Distributional Dependence in the Becker-DeGroot-Marschak ...

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Id Det. Category Comment<br />

34 0 low I stuck with relatively low values <strong>the</strong> entire time<br />

35 0 spike I ei<strong>the</strong>r submitted <strong>the</strong> price that <strong>the</strong> item was most likely to be or a price closest to <strong>the</strong> most probable price.<br />

36 1 [N/A] [Failed to submit <strong>the</strong> end-of-experiment survey.]<br />

37 1 low for <strong>the</strong> first part i went about as low as i could,<br />

38 0 bimodal if 0 had a probability <strong>the</strong>n I chose it, but if not I chose below <strong>the</strong> first dollar amount with probability<br />

39 0 zero I did not want <strong>the</strong> item<br />

40 1 median i saw <strong>the</strong> trends on <strong>the</strong> graphs and took my value to be a median of <strong>the</strong> numbers on <strong>the</strong> chart<br />

41 1 zero I didn't want to spend anyth<strong>in</strong>g on cookies. Cookies are bad for you anyways.<br />

42 0 random Looked at probabilities. S<strong>in</strong>ce <strong>the</strong>y were all fairly low, I tended to choose values randomly.<br />

43 0 satisfaction looked at <strong>the</strong> probabilities and decided bett<strong>in</strong>g extremely high would most likely allow me to get equal to if<br />

not higher than <strong>the</strong> actual number<br />

44 1 predeterm<strong>in</strong>ed I submitted <strong>the</strong> value I placed on <strong>the</strong> item for each round, which was always 3.<br />

45 1 predeterm<strong>in</strong>ed I had about <strong>the</strong> same answer for every round ($3.00); <strong>the</strong> possibility of obta<strong>in</strong><strong>in</strong>g <strong>the</strong> item didn't matter<br />

because that's always <strong>the</strong> amount I'd pay (or slightly more, if <strong>the</strong> chances were more promis<strong>in</strong>g a slight but<br />

more significant percentage higher).<br />

46 0 predeterm<strong>in</strong>ed 0.50 was <strong>the</strong> most I was will<strong>in</strong>g to pay for a dozen cookies.<br />

47 0 predeterm<strong>in</strong>ed I valued <strong>the</strong> item at $4<br />

48 1 preference Personal preference<br />

49 1 o<strong>the</strong>r <strong>in</strong>st<strong>in</strong>ct.<br />

50 0 zero as <strong>the</strong> round pass, I decided to not get <strong>the</strong> cookie s<strong>in</strong>ce it seemed like I had to pay lot of money for it<br />

51 0 median I stayed around <strong>the</strong> middle of <strong>the</strong> range of numbers and guessed slightly on <strong>the</strong> lower side. If <strong>the</strong>re was a<br />

higher probability, I guessed closer to that side.<br />

52 1 predeterm<strong>in</strong>ed By what <strong>the</strong> item was worth to me.<br />

53 1 predeterm<strong>in</strong>ed Basically accord<strong>in</strong>g to my personal <strong>in</strong>terest <strong>in</strong> <strong>the</strong> cookie, I don't want to put more money than $1 on it.<br />

54 0 probability prob.<br />

55 0 probability i decided base on what percentages that im likely to get <strong>the</strong> item<br />

56 1 predeterm<strong>in</strong>ed 50 cents per cookie, $6 total, for every round<br />

57 1 probability i chose amount to put <strong>in</strong> based on where <strong>the</strong> blue graph l<strong>in</strong>es were. if <strong>the</strong>re were many blue l<strong>in</strong>es on <strong>the</strong> right<br />

side of <strong>the</strong> graph, extend<strong>in</strong>g very high, i would put a larger value. if <strong>the</strong>re were higher blue bars on <strong>the</strong> left, my<br />

value would be where <strong>the</strong> graph l<strong>in</strong>es stopped show<strong>in</strong>g a high percentage. i didnt really keep <strong>the</strong> value of <strong>the</strong><br />

cream certificate <strong>in</strong> m<strong>in</strong>d, just <strong>the</strong> likelihood of whatever amount i might put <strong>in</strong> that round would be mean i<br />

had a better chance at w<strong>in</strong>n<strong>in</strong>g.<br />

58 0 o<strong>the</strong>r i thought that too high would decrease my money (and if i even got <strong>the</strong> cookies, id just b<strong>in</strong>ge), and too low<br />

would waste <strong>the</strong> chance at a free gift card<br />

59 0 bimodal If <strong>the</strong> distribute was over 5.00, I chose 4.00 so I would not be pay<strong>in</strong>g more for a card that I did not value over<br />

3.00. If <strong>the</strong> distribution had over a 50% chance of be<strong>in</strong>g under 3.00, I chose 2.50 for my value.<br />

60 1 hybrid by how likely it was that I could get it for a specific price<br />

61 1 bimodal If <strong>the</strong>re was an equal amount of chance for <strong>the</strong> item to be at a low cost, <strong>the</strong>n I would bet a low amount of<br />

money, but if it was a graph with a probability that <strong>in</strong>creased to a higher number, I would not bet any money,<br />

and if <strong>the</strong>re was no probability for anyth<strong>in</strong>g lower than a dollar I would not bet any mo<strong>the</strong>r.<br />

62 0 hybrid I did not want to pay more than 5. If it was very likely to be less than five my will<strong>in</strong>gness to pay went dow[n]<br />

because i expected it to be less than 5.<br />

63 0 predeterm<strong>in</strong>ed I put $5-6 on all rounds as that is what I am will<strong>in</strong>g to sacrifice for it. And I would be perfectly content if <strong>in</strong> 1<br />

round <strong>the</strong> value of it was rolled as 0 and I gave $5-6 for someth<strong>in</strong>g I could have gotten for 0.<br />

64 1 predeterm<strong>in</strong>ed I looked at <strong>the</strong> charts, but basically I had already decided how much I wanted to risk.<br />

65 1 preference Based on personal preference.<br />

66 0 mean by th<strong>in</strong>k<strong>in</strong>g about <strong>the</strong> average values.<br />

67 0 4 th quartile Whichever value was <strong>the</strong> highest, I would enter that value<br />

68 1 bimodal If <strong>the</strong>re was a high likelihood for <strong>the</strong> price to around 3.00 or less, I valued it at 3.50. If it was unlikely, I kept<br />

<strong>the</strong> price at 3.00.<br />

69 1 probability Based on probability of values<br />

83

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