01.02.2015 Views

arc-flash analysis of utility power systems - Michigan Technological ...

arc-flash analysis of utility power systems - Michigan Technological ...

arc-flash analysis of utility power systems - Michigan Technological ...

SHOW MORE
SHOW LESS

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

" : ) % & 6 7<br />

=9 " (3.7)<br />

<<br />

where<br />

E = incident energy (cal/cm 2 )<br />

V = system voltage (kV)<br />

t = <strong>arc</strong>ing time (seconds)<br />

D = working distance (mm)<br />

I a<br />

= bolted fault current (kA)<br />

The next step in the calculations is to determine the <strong>flash</strong> protection boundary.<br />

This is an approach distance at which a worker will receive a second-degree burn if an<br />

<strong>arc</strong> <strong>flash</strong> would occur; this is the level <strong>of</strong> 1.2 cal/cm 2 . (3.8) provides the equation to<br />

determine this distance<br />

> " " 4 5 & 6 7<br />

9 8 6:8; 9A<br />

2 @<br />

B<br />

;<br />

(3.8)<br />

where<br />

D b<br />

C f<br />

E a<br />

= distance <strong>of</strong> <strong>flash</strong> protection boundary from <strong>arc</strong> (mm)<br />

= calculation factor <strong>of</strong> 1.5 for voltages less than or equal to 1 kV<br />

= normalized incident energy<br />

E b = incident energy in J/cm 2 at the <strong>flash</strong> protection boundary: typically 5<br />

J/cm 2 which is equal to 1.2 cal/cm 2<br />

t = <strong>arc</strong>ing time (seconds)<br />

X = distance exponent<br />

610 = normalized distance <strong>of</strong> 24 inches converted to millimeters<br />

0.2 = normalized 0.2 second clearing time<br />

(3.8) is based on the current being interrupted by a non-current limiting device.<br />

Additional equations are needed if these devices are present.<br />

14

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!