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331<br />
Ans<br />
<strong>Marking</strong> scheme<br />
( )<br />
……..(1)<br />
( )<br />
……….(12)<br />
from ( ) and ( )<br />
ITEM – 11<br />
1<br />
1<br />
putting d =3 in eq (1)<br />
( )<br />
1<br />
<strong>Marking</strong> scheme<br />
Given equation is =0<br />
ITEM – 12<br />
let<br />
so,<br />
1<br />
table for<br />
x 0 1 -1 2 -2<br />
y 0 3 3 12 12<br />
Table for<br />
x 0 -1 -2 -3<br />
1<br />
y -2 3 8 13<br />
for graph: 1<br />
conclusion :<br />
here the parabola and the straight line intersect at point<br />
1<br />
( ) ( ) so the requird solutions are<br />
ITEM-13<br />
<strong>Marking</strong> scheme<br />
(i) The given equation is matrix form is :<br />
* + * + = * +<br />
i.e. = B, where * + * + and * +<br />
1<br />
| | * + #0<br />
(ii) Working out<br />
–<br />
= * +<br />
⁄<br />
– ⁄<br />
1<br />
(iii) Expressing in the form<br />
–<br />
[– ⁄ ⁄ ]<br />
5
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