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Marking Scheme

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* +<br />

= * +<br />

⁄<br />

– ⁄<br />

[– ⁄ ⁄ ]<br />

* +<br />

(iv) Find out the correct values of x and y<br />

x= 3<br />

y = 4 1<br />

1<br />

331<br />

<strong>Marking</strong> scheme<br />

(i)<br />

ITEM_14<br />

i.e. slope ( ) 1<br />

(ii) Slope of parallel line 1<br />

(iii) ( ) 1<br />

(iv)<br />

Required equation is 1<br />

ITEM-15<br />

<strong>Marking</strong> scheme<br />

(i) Given that general equation of 1 st degree are<br />

a 1 x + b 1 y+c 1 = 0 -----------------(i)<br />

a 2 x+b 2 y+c 2 = 0 -----------------(ii)<br />

Equation passing through the origin and parallel to the lines<br />

(i) and (ii) are<br />

(a 1 x + b 1 y = 0 --------(iii)<br />

a 2 x+b 2 y = 0------- (iv) respectively 1<br />

(ii) Multiplying equation (iii) and (iv)<br />

(a 1 x+ b 1 y) (a 2 x + b 2 y) = 0 --------(v)<br />

a 1 a 2 x 2 + a 1 b 2 xy + a 2 b 1 xy+ b 1 b 2 y 2 =0 1<br />

<strong>Marking</strong> scheme<br />

(iii) a 1 a 2 x 2 ( a 1 b 2 + a 2 b 1 ) xy + b 1 b 2 y 2 =0<br />

Substituting a 1 a 2 = a b 1 b 2 = b and<br />

( a 1 b 2 + a 2 b 1 ) = 2h in above equation 1<br />

(iv) ax 2 + 2xy + by 2 = 0<br />

Which represent the homogeneous equation of second degree<br />

ITEM –16<br />

1<br />

i<br />

Finding the center of circle from the given points and equations<br />

…………(i)<br />

………(ii)<br />

1<br />

ii ( ) ( ) 1<br />

iii<br />

iv<br />

calculating the exact radius<br />

( )<br />

√<br />

Equation of required circle<br />

ITEM-17<br />

1<br />

1<br />

6

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