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* +<br />
= * +<br />
⁄<br />
– ⁄<br />
[– ⁄ ⁄ ]<br />
* +<br />
(iv) Find out the correct values of x and y<br />
x= 3<br />
y = 4 1<br />
1<br />
331<br />
<strong>Marking</strong> scheme<br />
(i)<br />
ITEM_14<br />
i.e. slope ( ) 1<br />
(ii) Slope of parallel line 1<br />
(iii) ( ) 1<br />
(iv)<br />
Required equation is 1<br />
ITEM-15<br />
<strong>Marking</strong> scheme<br />
(i) Given that general equation of 1 st degree are<br />
a 1 x + b 1 y+c 1 = 0 -----------------(i)<br />
a 2 x+b 2 y+c 2 = 0 -----------------(ii)<br />
Equation passing through the origin and parallel to the lines<br />
(i) and (ii) are<br />
(a 1 x + b 1 y = 0 --------(iii)<br />
a 2 x+b 2 y = 0------- (iv) respectively 1<br />
(ii) Multiplying equation (iii) and (iv)<br />
(a 1 x+ b 1 y) (a 2 x + b 2 y) = 0 --------(v)<br />
a 1 a 2 x 2 + a 1 b 2 xy + a 2 b 1 xy+ b 1 b 2 y 2 =0 1<br />
<strong>Marking</strong> scheme<br />
(iii) a 1 a 2 x 2 ( a 1 b 2 + a 2 b 1 ) xy + b 1 b 2 y 2 =0<br />
Substituting a 1 a 2 = a b 1 b 2 = b and<br />
( a 1 b 2 + a 2 b 1 ) = 2h in above equation 1<br />
(iv) ax 2 + 2xy + by 2 = 0<br />
Which represent the homogeneous equation of second degree<br />
ITEM –16<br />
1<br />
i<br />
Finding the center of circle from the given points and equations<br />
…………(i)<br />
………(ii)<br />
1<br />
ii ( ) ( ) 1<br />
iii<br />
iv<br />
calculating the exact radius<br />
( )<br />
√<br />
Equation of required circle<br />
ITEM-17<br />
1<br />
1<br />
6