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Summary 2. The electromechanical energy conversion

Summary 2. The electromechanical energy conversion

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Comparing this expression with the <strong>energy</strong> balance of the circuit, we find that the total electric<br />

power inlet (on the left of the equation) is divided into three contributions:<br />

• power dissipated in the resistance<br />

2<br />

p p<br />

= Ri<br />

• power related to the magnetic field<br />

• mechanical power<br />

p<br />

µ<br />

di 1 2<br />

= Li + i<br />

dt 2<br />

1 2 dL<br />

p m<br />

= i<br />

2 dt<br />

If we consider that the inductance in the reference frame varies with periodic sinusoidal pattern,<br />

you can highlight an expression for the anisotropy torque:<br />

1 2 dL 1 2 dL dθ<br />

1 2 dL<br />

p m<br />

= i = i = i Ω<br />

2 dt 2 dθ<br />

dt 2 dθ<br />

pm<br />

1 2 dL<br />

Tm<br />

= = i<br />

Ω 2 dθ<br />

Now, suppose you change the old structure so as to also include a winding on the rotating part as<br />

in Figure 2-3.<br />

dL<br />

dt<br />

θ<br />

i 2<br />

v 2<br />

v 1<br />

i 1<br />

Figure 2-3: reluctance and excitation torque in a primitive machine<br />

<strong>The</strong> equations describing this structure are that of a mutual inductor with variable parameters.<br />

You can then write:<br />

d d<br />

v1<br />

= R1i1<br />

+ ( L1i1<br />

) + ( Lmi2<br />

)<br />

dt dt<br />

d d<br />

v2<br />

= R2i2<br />

+ ( L2i2<br />

) + ( Lmi1<br />

)<br />

dt dt<br />

and developing the derivatives:<br />

di1<br />

dL1<br />

di2<br />

dLm<br />

v1<br />

= R1i1<br />

+ L1<br />

+ i1<br />

+ Lm<br />

+ i2<br />

dt dt dt dt<br />

di2<br />

dL2<br />

di1<br />

dLm<br />

v2<br />

= R2i2<br />

+ L2<br />

+ i2<br />

+ Lm<br />

+ i1<br />

dt dt dt dt<br />

4

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