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MHR • Advanced Functions 12 Solutions 660

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Chapter 7 Section 2 Question 8 Page 376<br />

! 1$<br />

a) A(t) = A 0<br />

"<br />

# 2%<br />

&<br />

!<br />

17 = 20 1 $<br />

"<br />

# 2%<br />

&<br />

17<br />

20 = ! 1 $<br />

"<br />

# 2%<br />

&<br />

5<br />

h<br />

t<br />

h<br />

5<br />

h<br />

!<br />

log0.85 = log 1 $<br />

"<br />

# 2%<br />

&<br />

5<br />

h<br />

log0.85 = 5 h log 1 2<br />

5<br />

h = log0.85<br />

log 1 2<br />

h =<br />

5log 1 2<br />

log0.85<br />

h &= 21.3<br />

The half-life of thorium-233 is approximately 21.3 min.<br />

!<br />

b) 1 = 20 1 $<br />

"<br />

# 2%<br />

&<br />

1<br />

20 = ! 1 $<br />

"<br />

# 2%<br />

&<br />

t<br />

21.3<br />

!<br />

log0.05 = log 1 $<br />

"<br />

# 2%<br />

&<br />

t<br />

21.3<br />

t<br />

21.3<br />

log0.05 =<br />

t<br />

21.3 log 1 2<br />

t<br />

21.3 = log0.05<br />

log 1 2<br />

t = 21.3log0.05<br />

log 1 2<br />

t &= 92.06<br />

It will take approximately 92.06 min for the sample to decay to 1 mg (92.17 min using the<br />

exact half-life).<br />

<strong>MHR</strong> <strong>•</strong> <strong>Advanced</strong> <strong>Functions</strong> <strong>12</strong> <strong>Solutions</strong> 680

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