MHR • Advanced Functions 12 Solutions 660
MHR • Advanced Functions 12 Solutions 660
MHR • Advanced Functions 12 Solutions 660
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Chapter 7 Section 2 Question 8 Page 376<br />
! 1$<br />
a) A(t) = A 0<br />
"<br />
# 2%<br />
&<br />
!<br />
17 = 20 1 $<br />
"<br />
# 2%<br />
&<br />
17<br />
20 = ! 1 $<br />
"<br />
# 2%<br />
&<br />
5<br />
h<br />
t<br />
h<br />
5<br />
h<br />
!<br />
log0.85 = log 1 $<br />
"<br />
# 2%<br />
&<br />
5<br />
h<br />
log0.85 = 5 h log 1 2<br />
5<br />
h = log0.85<br />
log 1 2<br />
h =<br />
5log 1 2<br />
log0.85<br />
h &= 21.3<br />
The half-life of thorium-233 is approximately 21.3 min.<br />
!<br />
b) 1 = 20 1 $<br />
"<br />
# 2%<br />
&<br />
1<br />
20 = ! 1 $<br />
"<br />
# 2%<br />
&<br />
t<br />
21.3<br />
!<br />
log0.05 = log 1 $<br />
"<br />
# 2%<br />
&<br />
t<br />
21.3<br />
t<br />
21.3<br />
log0.05 =<br />
t<br />
21.3 log 1 2<br />
t<br />
21.3 = log0.05<br />
log 1 2<br />
t = 21.3log0.05<br />
log 1 2<br />
t &= 92.06<br />
It will take approximately 92.06 min for the sample to decay to 1 mg (92.17 min using the<br />
exact half-life).<br />
<strong>MHR</strong> <strong>•</strong> <strong>Advanced</strong> <strong>Functions</strong> <strong>12</strong> <strong>Solutions</strong> 680