MHR • Advanced Functions 12 Solutions 660
MHR • Advanced Functions 12 Solutions 660
MHR • Advanced Functions 12 Solutions 660
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!<br />
b) 0.05 = 1 $<br />
"<br />
# 2%<br />
&<br />
t<br />
5<br />
log0.05 = t 5 log 1 2<br />
t<br />
5 = log0.05<br />
log 1 2<br />
t = 5log0.05<br />
log 1 2<br />
t &= 21.6<br />
It takes approximately 21.6 min for the sample to decay to 5% of its initial amount.<br />
Chapter 7 Review Question 5 Page 408<br />
a) log3 x!2 = log5 x<br />
(x ! 2)log3 = x log5<br />
x log3! 2log3 = x log5<br />
x log3! x log5 = 2log3<br />
x(log3! log5) = 2log3<br />
x =<br />
2log3<br />
log3! log5<br />
b) log 2 k !2 = log3 k +1<br />
(k ! 2)log 2 = (k +1)log3<br />
k log 2 ! 2log 2 = k log3+ log3<br />
k log 2 ! k log3 = 2log 2 + log3<br />
k(log 2 ! log3) = 2log 2 + log3<br />
k =<br />
2log 2 + log3<br />
log 2 ! log3<br />
<strong>MHR</strong> <strong>•</strong> <strong>Advanced</strong> <strong>Functions</strong> <strong>12</strong> <strong>Solutions</strong> 736
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