MHR • Advanced Functions 12 Solutions 660
MHR • Advanced Functions 12 Solutions 660
MHR • Advanced Functions 12 Solutions 660
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# I &<br />
b) 20 = 10 log<br />
$<br />
%<br />
1.0 !10 "<strong>12</strong> '<br />
(<br />
( ) = I<br />
100 1.0 !10 "<strong>12</strong><br />
# I &<br />
2 = log<br />
$<br />
%<br />
1.0 !10 "<strong>12</strong> '<br />
(<br />
10 2 I<br />
=<br />
1.0 !10 "<strong>12</strong><br />
I = 1!10 "10<br />
The whisper’s intensity is 1 × 10 –10 W/m 2 .<br />
# I &<br />
c) <strong>12</strong>0 = 10 log<br />
$<br />
%<br />
1.0 !10 "<strong>12</strong> '<br />
(<br />
10 <strong>12</strong> 1.0 !10 "<strong>12</strong><br />
# I &<br />
<strong>12</strong> = log<br />
$<br />
%<br />
1.0 !10 "<strong>12</strong> '<br />
(<br />
10 <strong>12</strong> I<br />
=<br />
1.0 !10 "<strong>12</strong><br />
( ) = I<br />
I = 1<br />
The car stereo’s intensity is 1 W/m 2 .<br />
Chapter 7 Section 4 Question 9 Page 392<br />
a) No, the statement is not true since log (–3) and log (–4) are undefined.<br />
b) Yes.<br />
L.S. = ! log3! log 4<br />
= !(log3+ log 4)<br />
= ! #<br />
$ log(3" 4) %<br />
&<br />
= ! log<strong>12</strong><br />
R.S. = ! log<strong>12</strong><br />
Since L.S. = R.S., –log 3 – log 4 = –log <strong>12</strong>.<br />
<strong>MHR</strong> <strong>•</strong> <strong>Advanced</strong> <strong>Functions</strong> <strong>12</strong> <strong>Solutions</strong> 715
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