MHR • Advanced Functions 12 Solutions 660

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f) 40 = 94.54(0.978) t log 40 94.54 = log(0.978)t log 40 = t log 0.978 94.54 log 40 t = 94.54 log 0.978 t &= 38.7 30 = 94.54(0.978) t log 30 94.54 = log(0.978)t log 30 = t log 0.978 94.54 log 30 t = 94.54 log 0.978 t &= 51.6 0 = 94.54(0.978) t 0 log 94.54 = log(0.978)t 0 log = t log 0.978 94.54 0 log t = 94.54 log 0.978 t!is!undefined This makes sense because the water cannot cool less than room temperature. Chapter 7 Section 5 Question 10 Page 406 " a) 150 !120 = 10log I % 2 $ ' # & I 1 " 30 = 10log I % 2 $ ' # & I 1 " 3 = log I % 2 $ ' # & 10 3 = I 2 I 1 I 1 1000 = I 2 I 1 The ratio of the intensities is 1000. Rocco’s signal needs to be boosted to match Biff’s sound level. 1 b) 1000 ÷ = 1000 !10 000 10 000 = 10 000 000 = 10 7 The sound crew should reduce the drums by a factor of 10 7 . Chapter 7 Section 5 Question 11 Page 406 Solutions to Achievement Check questions are provided in the Teacher’s Resource. MHR • Advanced Functions 12 Solutions 727
Chapter 7 Section 5 Question 12 Page 407 Answers may vary. A sample solution is shown. a), b) Data on carbon-dating that gives the approximate age of piece of organic material, and the ratio of the current amount of carbon-14 to the expected original amount. Age (years) Carbon-14 Ratio 750 0.91 1000 0.88 2400 0.74 2850 0.70 4000 0.61 7500 0.39 8200 0.36 c) d) Knowing that carbon dating involves a half-life, the exponential regression is the best. MHR • Advanced Functions 12 Solutions 728
Page 1 and 2:
Chapter 7 Tools and Strategies for
Page 3 and 4:
c) x 2 + x !1 = 0 x = !1± 12 ! 4(1
Page 5 and 6:
Chapter 7 Prerequisite Skills Quest
Page 7 and 8:
Chapter 7 Section 1 Question 4 Page
Page 9 and 10:
) c) d) Chapter 7 Section 1 Questio
Page 11 and 12:
Chapter 7 Section 1 Question 10 Pag
Page 13 and 14:
Page 15 and 16:
Page 17 and 18: Chapter 7 Section 2 Techniques for
Page 19 and 20: c) Answers may vary. A sample solut
Page 21 and 22: Chapter 7 Section 2 Question 8 Page
Page 23 and 24: Chapter 7 Section 2 Question 10 Pag
Page 25 and 26: f) 4 x ! 3!18(4 ! x ) = 0 (4 x ) 2
Page 27 and 28: d) e) There is no zero so there is
Page 37 and 38: d) 2log w + 3log w + 1 2 log ! 1 $
Page 43 and 44: ) Let x = log b m and y = log b n b
Page 47 and 48: Chapter 7 Section 4 Techniques for
Page 51 and 52: Check: d) 1 = log( y + 9) ! log y "
Page 53 and 54: ! f) log p + 5 $ " # p +1% & = 3 p
Page 65 and 66: ) i) y &= 4.21x - 3.07 ii) y &= 0.8
Page 67: Chapter 7 Section 5 Question 8 Page
Page 75 and 76: Chapter 7 Review Chapter 7 Review Q
Page 77 and 78: ! b) 0.05 = 1 $ " # 2% & t 5 log0.0
Page 79 and 80: Chapter 7 Review Question 7 Page 40
Page 81 and 82: Chapter 7 Review Question 13 Page 4
Page 83 and 84: d) i) A = 500(1.033) 2t + 500(0.01)
Page 85 and 86: Chapter 7 Practice Test Question 6
Page 87 and 88: d) Chapter 7 Practice Test Question
Page 89 and 90: Chapter 7 Practice Test Question 10
Page 91: e) i) y &= 95.67(0.96) 15 y &= 49.6
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MHR • Advanced Functions 12 Solutions 660

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