MHR • Advanced Functions 12 Solutions 660
MHR • Advanced Functions 12 Solutions 660
MHR • Advanced Functions 12 Solutions 660
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Chapter 7 Section 4<br />
Techniques for Solving Logarithmic<br />
Equations<br />
Chapter 7 Section 4 Question 1 Page 391<br />
a) log(x ! 2) = 1<br />
x ! 2 = 10 1<br />
x = 10 + 2<br />
x = <strong>12</strong><br />
d) 1! log(w ! 7) = 0<br />
1 = log(w ! 7)<br />
10 = w ! 7<br />
10 + 7 = w<br />
w = 17<br />
b) 2 = log(x + 25)<br />
10 2 = x + 25<br />
100 ! 25 = x<br />
x = 75<br />
e) log(k ! 8) = 2<br />
k ! 8 = 10 2<br />
k = 100 + 8<br />
k = 108<br />
c) 4 = 2log( p + 62)<br />
2 = log( p + 62)<br />
10 2 = p + 62<br />
100 ! 62 = p<br />
p = 38<br />
f) 6 ! 3log 2n = 0<br />
6 = 3log 2n<br />
2 = log 2n<br />
10 2 = 2n<br />
100<br />
2 = n<br />
n = 50<br />
Check:<br />
a) log(<strong>12</strong> – 2) = 1 b) 2 = log(75 + 25) c) 4 = 2log(38 + 62)<br />
d) 1 – log (17 – 7) e) log(108 – 8) = 2 f) 6 – 3log 2(50) = 0<br />
<strong>MHR</strong> <strong>•</strong> <strong>Advanced</strong> <strong>Functions</strong> <strong>12</strong> <strong>Solutions</strong> 706
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