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MHR • Advanced Functions 12 Solutions 660

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e) i) y &= 95.67(0.96) 15<br />

y &= 49.6<br />

The tea is approximately 49.6°C after 15 min.<br />

ii) 38 &= 95.67( 0.96) x<br />

0.40 &= 0.96 x<br />

log0.40 &= x log0.96<br />

x &= log0.40<br />

log0.96<br />

x &= 21.1<br />

It would take approximately 21.1 min for the tea to reach 38°C.<br />

f) Answers may vary. A sample solution is shown.<br />

The temperature of the room was constant.<br />

<strong>MHR</strong> <strong>•</strong> <strong>Advanced</strong> <strong>Functions</strong> <strong>12</strong> <strong>Solutions</strong> 750

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