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• The frequency response foraverage filter isFiltering Sampled Continuous-Time Signalsin the general moving• The frequency response at these two frequencies isHe j0.2 He j0.6 (6.41)sin2.50.2= --------------------------------------e – j20.2 = 0.6472e – j0.45sin0.2 2(6.42)sin2.50.6= --------------------------------------e – j20.6 = – 0.2472e – j1.25sin0.6 2>> diric(0.2*pi,5)ans = 0.6472He jˆ>> diric(0.6*pi,5)=L = 5sin2.5ˆ5 --------------------------e – j2ˆsinˆ 2 0.2472e – j0.2ans = -0.2472 % also = 0.2472 at angle +/- pi• The filter output yn isyn = 0.6472cos0.2n – 0.4+ 0.7416cos0.2n – 1.2 + and the D-to-C output isyt =0.6472cos2100t – 0.4+ 0.7416cos2300t – 0.2(6.43)(6.44)ECE 2610 Signals and Systems 6–31
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