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Sinusoidal <strong>Response</strong> <strong>of</strong> <strong>FIR</strong> Systems>> xlabel('hat(\omega) (rad)')8Magnitude6423.248Phase (rad)00 1 2 3 4 5 620−2–-20 1 2 3 4 5 6hat(ω) (rad)22Example: Findyn for Input• The input frequency isthe phase is = 0xn = 5e j1 nˆ 0 = 1rad, the amplitude is 5, and• Assuming xn is input to the 4-tap <strong>FIR</strong> filter in the previousexample, the filter output isyn = 3 + 2cos1+ 2cos2 1e j1 2= 16.2415e – j2 e jn• The amplitude response or gain at ˆ 0 = 1 is He j1 =3.248; why?– 5e j1 nECE 2610 Signals and Systems 6–5
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