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Course in Probability Theory

Course in Probability Theory

Course in Probability Theory

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14 1 DISTRIBUTION FUNCTIONbecomes obvious if we proceed step by step and observe thatJn+1,2k = Jn,k, Cn+1,2k = Cn,k for 1 < k < 2n - 1 .The value of F is constant on each J n , k and is strictly greater on any otherJ n ', k ' situated to the right of J n , k . Thus F is <strong>in</strong>creas<strong>in</strong>g and clearly we havelim F(x) = 0, lim F(x) = 1 .xyoxt1Let us complete the def<strong>in</strong>ition of F by sett<strong>in</strong>gF(x) = 0 for x < 0, F(x) = 1 for x > 1 .F is now def<strong>in</strong>ed on the doma<strong>in</strong> D = (- oo, 0) U U U (1, oo) and <strong>in</strong>creas<strong>in</strong>gthere . S<strong>in</strong>ce each J n , k is at a distance > 1/3n from any dist<strong>in</strong>ct Jn,k' and thetotal variation of F over each of the 2' disjo<strong>in</strong>t <strong>in</strong>tervals that rema<strong>in</strong> afterremov<strong>in</strong>g J n , k , 1 < k < 2n - 1, is 1/2n, it follows that0

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