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EN 14766:2005 - 64_e_stf - Baltik vairas

EN 14766:2005 - 64_e_stf - Baltik vairas

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<strong>EN</strong> <strong>14766</strong>:<strong>2005</strong> (E)∑ xy , ∑ x2No.1234, x and y are calculated as shown:x(pedal force)N90150230300Sum∑ x = 770∑ y = 590Mean x = 192, 5y = 147, 5y(braking force)N90120160220No. xy x 212348 10018 00036 80066 0008 10022 50052 90090 000Sum∑ xy = 1289002∑ x = 173500b =∑∑xy − yx2− x∑∑xx128900 − (147,5×770)=173500 − (192,5×770)= 0,606a = y − bx= 147,5− (0,606x192,5)= 30,8The line of best fit is therefore:y = 30 ,8 + 0, 606xand the ± 20 % limit lines are:80ylower= (30,8 + 0,606x)100= 24,<strong>64</strong> + 0,485x120yupper= (30,8 + 0,606x)100= 36,96 + 0,727xThe results are shown graphically in Figure A.1.85

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