6. Minimizing Delay
6. Minimizing Delay
6. Minimizing Delay
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Logical Effort from previous tablet inv = p inv Cout /3.6ff t n2 = p n2 g N2 Cout / 4.2ff Inverter' s average slope gives∗1ff /3.6ff =3.45pS=12.42pSInverter ' s averageintrinsic delay gives∗p inv=20pSp inv =1.61Nand2 ' s average slope gives∗g N2 ∗1ff /4.2fF=3.68g n2 =1.25Logical effort of NAND2 is less than 4/3 (1.33), why?
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