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Why Read This Book? - Index of

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Strong Induction<br />

3.5 Variations <strong>of</strong> the PMI 89<br />

There is another way to build the set S on p. 80. Consider the following. Suppose<br />

S is a subset <strong>of</strong> the positive integers that has the following properties.<br />

(K1) 1 ∈ S<br />

(K2) If n ≥ 2 and 1, 2,...,n− 1 ∈ S, then n ∈ S.<br />

Then by yet another mimicking <strong>of</strong> the pro<strong>of</strong> <strong>of</strong> Theorem 3.4.6, we could show that<br />

S = N. <strong>This</strong> is called the strong principle <strong>of</strong> mathematical induction, or SPMI.<br />

Theorem 3.5.17 (SPMI). Suppose S is a subset <strong>of</strong> the positive integers that has<br />

properties K1–K2. Then S = N.<br />

EXERCISE 3.5.18 <strong>This</strong> exercise addresses why Theorem 3.5.17 is called strong<br />

induction. To do so, we alter property I 2 slightly to read: If n ≥ 2 and n − 1 ∈ S,<br />

then n ∈ S. For each <strong>of</strong> the following pairs <strong>of</strong> statements, state which is stronger.<br />

(a) n ≥ 2 and n − 1 ∈ S n ≥ 2 and 1, 2,...,n− 1 ∈ S<br />

(b) Property I 2 Property K2<br />

(c) Properties I 1–I 2 Properties K1–K2<br />

(d) If I 1 and I 2, then S = N. If K1 and K2, then S = N.<br />

<strong>This</strong> is why the SPMI can be more powerful than the PMI. If we are required<br />

to prove a result is true for all n ≥ 1 and induction seems to be the way to go,<br />

we might find that regular induction does not provide us with a strong enough<br />

assumption to make the inductive leap. With either form <strong>of</strong> induction, we would<br />

still need to show that 1 ∈ S. But to make the inductive step, regular induction<br />

would only allow us to assume n ∈ S and require us to conclude n + 1 ∈ S solely<br />

from this. On the other hand, strong induction allows us to assume that all <strong>of</strong><br />

1, 2,...,n− 1 ∈ S, and requires us to conclude n ∈ S from this more extensive set<br />

<strong>of</strong> assumptions. 19<br />

In Section 2.5 we defined a positive integer to be prime provided it has exactly<br />

two distinct positive integer factors. An integer n ≥ 2 that is not prime is called<br />

composite, and such a number can be written in the form n = ab, where a and<br />

b are positive integers strictly less than n. The following theorem addresses the<br />

factorization <strong>of</strong> positive integers into a product <strong>of</strong> primes. We use a slight variation<br />

<strong>of</strong> the SPMI by rooting it at n = 2.<br />

Theorem 3.5.19 (Fundamental Theorem <strong>of</strong> Arithmetic). Every integer n≥<br />

2 can be written as the product <strong>of</strong> primes, and this factorization is unique, except<br />

perhaps for the order in which the factors are written.<br />

19 Actually, strong induction is no stronger than regular induction. They are logically equivalent.

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