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Why Read This Book? - Index of

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316 Chapter 9 Rings<br />

existence <strong>of</strong> multiplicative inverses. Thus there is only one thing to show in the<br />

next exercise.<br />

EXERCISE 9.8.11 A finite integral domain is a field. 6<br />

By Exercise 9.8.11, we have that Zp is a field if and only if p is prime.<br />

EXERCISE 9.8.12 Find multiplicative inverses for all nonzero elements <strong>of</strong> Z7.<br />

In the integers, you showed in Exercise 2.5.5 that if a | b and b | a, then a =±b.<br />

Furthermore, ±1 are the units in the integers. In a general domain, we say that<br />

a and b are associates if a | b and b | a. Since this definition does not apply to<br />

zero, we declare zero to be an associate <strong>of</strong> itself. Notice that this declaration<br />

and the definition <strong>of</strong> associate prevent zero from having any other associates in<br />

a domain.<br />

EXERCISE 9.8.13 Show that 1 + i and 1 − i are associates in the Gaussian<br />

integers Z[i].<br />

EXERCISE 9.8.14 In a domain, two elements a and b are associates if and only<br />

if there exist units u and v such that a = ub and b = va.<br />

You should feel an equivalence relation coming on about now.<br />

EXERCISE 9.8.15 Let D be a domain, and define a ∼ b if a is an associate <strong>of</strong> b.<br />

Then ∼ is an equivalence relation on D. 7<br />

Anytime you create an equivalence relation, it is natural to ask two questions:<br />

What do the equivalence classes look like, and which element from each<br />

equivalence class might be a good choice as a representative element <strong>of</strong> the class?<br />

EXERCISE 9.8.16 If D is a domain and ∼ is the equivalence relation <strong>of</strong><br />

association, then [e] is the set <strong>of</strong> units <strong>of</strong> D.<br />

If a and b are associates, then there ought to be some senses in which they<br />

are interchangeable. One example <strong>of</strong> how this is true is in the integers, where<br />

(6) = (−6). Associates generate the same principal ideal. The best way to show<br />

this is first to prove the following. Its corollary is immediate.<br />

EXERCISE 9.8.17 Suppose a and b are elements <strong>of</strong> a domain. Then a | b if and<br />

only if (b) ⊆ (a).<br />

6 To find a −1 , define f(x) = ax and apply Exercise 4.6.11.<br />

7 Don’t forget zero.

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