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Why Read This Book? - Index of

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238 Chapter 7 Functions <strong>of</strong> a Real Variable<br />

lines) is bounded, then f is uniformly continuous. The converse <strong>of</strong> Exercise 7.7.3<br />

is not true. Shortly, we will point out a function f that is uniformly continuous on<br />

a set A, but for which inequality (7.39) does not hold across A for any m>0.<br />

Naturally, we want to include a demonstration that a continuous function need<br />

not be uniformly continuous on a set.<br />

EXERCISE 7.7.4 What does it mean for f not to be uniformly continuous on A?<br />

Example 7.7.5 Show that f(x) = 1/x is not uniformly continuous on (0, 1).<br />

Solution First, we do some scratchwork. The vertical asymptote at x = 0 will<br />

provide us with x and y values that are very close together but whose functional<br />

values can differ as much as a strategically chosen ɛ-value. We have to play with<br />

the inequality<br />

� �<br />

�<br />

�<br />

1 1 �<br />

� − �<br />

x y �<br />

= |y − x|<br />

|x||y|<br />

≥ ɛ (7.40)<br />

and find some ɛ>0 so that, regardless <strong>of</strong> δ>0, we can find two points x and y<br />

that are within δ <strong>of</strong> each other and satisfy inequality (7.40). No obvious ɛ-value<br />

jumps out at us, so let’s try ɛ = 1 and see if we can proceed.<br />

Inequality (7.40) itself suggests a way to find x and y. Whatever we decide to<br />

let x be, we can let y = x + δ/2 so that |y − x| = δ/2

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