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Engineering Chemistry S Datta

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98 ENGINEERING CHEMISTRY

Sol. From Van’t Hoff equation, we have

ln

K

K

P2

P1

= ∆H R

L

N

M

T − T

TT

2 1

1 2

Here, T 1

= 27°C = 300 K; T 2

= 37°C = 310 K.

log

log

K

P2

K

K

3.49 × 10

O

Q

P

K P1 = 3.49 × 10 –2 atm –1 ; K P2 = ?

∆H = – 11.2 Kcal = – 11200 cal; R = 1.987 cal deg –1 mol –1 .

P2

P1

=

− 2 =

∆H

2.303R

L

N

M

T − T

TT

2 1

1 2

− 11200

2.303 × 1.987

L

NM

O

Q

P

310 − 300

300 × 310

or, K P2 = 1.9038 × 10 –2 atm –1 .

O

QP

SHORT QUESTIONS AND ANSWERS

Q. 1. State First law with mathematical expressions.

Ans. See text page 68. Alternatively, it can be stated as the net energy of the universe

remains constant.

Q. 2. State intensive property of a system.

Ans. See text page 66.

Q. 3. Why is enthalpy more useful than internal energy?

Ans. Internal energy and ethalpy of a system are measured by keeping the volume and

the pressure constant, respectively. Since, in most of the reactions, they occur at atmospheric

pressure, so enthalpy is more useful than internal energy.

Q. 4. The molar heat of sublimation of a solid is always greater than the molar

heat of vaporization of the corresponding liquid. Why?

Ans. Since the molar heat of sublimation is the summation of heat of melting and heat

of vaporization so it is always greater than the heat of vaporization of the corresponding liquid.

Q. 5. When does the entropy of a substance become zero?

Ans. The entropy of a substance becomes zero when the substance is perfectly crystalline

i.e., ordered state and at the temperature of 0 K.

Q. 6. Derive Clapeyron-Clausius equation and mention its applications.

Ans. See text page 84.

Q. 7. Derive Gibbs-Helmholtz equation and mention its significance.

Ans. See text page 85.

Q. 8. What is enthalpy?

Ans. See text page 71.

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