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Engineering Chemistry S Datta

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218 ENGINEERING CHEMISTRY

Highlights:

• The change in volume throughout the course of titration must be kept small by

using a titrant which is at least 100 times more concentrated than the solution

being titrated.

• Measurements of conductance in the region of equivalence point are of little value

due to hydrolysis, dissociation or solubility of the reaction products. For this reason,

the graph shows a curvature rather than a clear intersection of the two straight

lines [Fig. 9.10(b)].

(a) Neutralisation Reactions

In the titration of a strong acid with a strong base, there is always an initial decrease in

conductance. The conductance then rises beyond the equivalence point. In the titration of

NaOH with HCl, the decrease in conductance is due to the replacement of OH – ions (molar

ionic conductivity = 199) by Cl – ions (molar ionic conductivity = 76). Beyond the equivalence

point, the increase in conductivity is due to excess of H + ions with very high ionic molar

conductivity (350).

In the titration of HCl with NaOH, the initial fall in conductance is due to the replacement

of H + ions (350) with Na + ions (50) and the rise beyond equivalence point is due to excess OH –

ions (199) [Fig. 9.10(a)].

Highlight:

The stronger the solution used for the titration, the sharper is the end point

(Fig. 9.10).

Conductivity falls as

OH (aq) ions are

neutralized

Conductivity

Conductivity of

+ –

Na Cl (aq)

Conductivity rises

due to excess

+

H (aq) ions added

End point

Conductance

Volume of HCl (aq) added

Volume of alkali

Fig. 9.10 (a) Changes in conductivity during titration Fig. 9.10 (b) Changes in conductivity

of NaOH(aq) with HCl(aq). In water H + (aq) during titration of a weak acid

and OH – (aq) ions are very mobile, so they (CH 3

COOH) (aq) with a strong

conduct electricity very well. base (NaOH) (aq).

(b) Precipitation Reactions

Conductometric titrations of this type may be performed if the reaction product is

sparingly soluble salt. The precipitate should be formed fairly rapidly and should not have

strong adsorbent properties. The titration of KCl solution vs AgNO 3

solution satisfies the above

conditions. The nature of the titration curve is as in Fig. 9.10 (c).

The point of intersection of the two curves is sharp. So, end point of the reaction can be

determined easily.

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