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The Nature of the Cooper Pair - University of Liverpool

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If V (r) is constant, <strong>the</strong> solution is <strong>of</strong> <strong>the</strong> form<br />

ψ(r) = sin(kr).<br />

However, V (r) is not constant. It becomes zero beyond r = l.<br />

We can try a sum <strong>of</strong> sine functions:<br />

Ψ(r) = �<br />

ak sin(kr),<br />

where a k are unknown constants that we must find.<br />

k<br />

We now come <strong>the</strong> <strong>the</strong> important part. <strong>The</strong> need for this sum<br />

means that energy states with many wavevectors k must be<br />

used to make up <strong>the</strong> wavefunction. However, we are not<br />

allowed to use k values below <strong>the</strong> Fermi energy, because those<br />

states are fully occupied.<br />

<strong>The</strong>refore, we must impose <strong>the</strong> condition that k must be more<br />

than k F , <strong>the</strong> wavevector at <strong>the</strong> Fermi energy.<br />

<strong>The</strong> detailed steps to solve <strong>the</strong> Schrodinger equation are given<br />

in <strong>the</strong> appendix.<br />

Superconductivity 19

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