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The Nature of the Cooper Pair - University of Liverpool

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<strong>The</strong> right hand side <strong>of</strong> <strong>the</strong> Schrodinger equation<br />

aε(ε + ∆) = −B<br />

is a constant. Let this be C. So<br />

or<br />

� �ωD<br />

0<br />

aε(ε + ∆) = C,<br />

aε = C<br />

ε + ∆ .<br />

a ε ′dε ′ .<br />

Substituting this back into <strong>the</strong> Schrodinger equation, we get<br />

Integrating, we find<br />

1 = −B<br />

� �ωD<br />

0<br />

dε ′<br />

ε ′ + ∆ .<br />

∆ = �ωD exp(−1/B) = �ωD exp(− 2πkF ).<br />

melV0<br />

Superconductivity 45

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