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BOGOLIUBOV SPECTRUM OF INTERACTING BOSE GASES 45<br />

Note that x �= 0 if u⊕v �= 0. Therefore, 0 is an eigenvalue of<br />

Xt := H +K − t2<br />

H −K .<br />

In fact, using Weyl sequences and arguing similarly, we also obtain<br />

t ∈ σ(ξ) = σ(SA) ⇔ 0 ∈ σ(Xt). (72)<br />

8. We show that the number of eigenvalues (with multiplicity) of ξ below<br />

µ := infσess(ξ) is equal to the number of negative eigenvalues of Xµ.<br />

Notethatthemappingt ↦→ Xt isstrictlydecreasing. Asaconsequence, for<br />

every j = 1,2,..., the min-max value λj(Xt) is a continuous and decreasing<br />

function on t ≥ 0. More precisely, if 0 ≤ t1 < t2, then λj(Xt1 ) ≥ λj(Xt2 )<br />

and the inequality is strict if λj(Xt1 ) is an eigenvalue of Xt1 . Moreover,<br />

and, for every t ∈ (0,µ),<br />

infσ(X0) = infσ(H +K) ≥ η > 0<br />

infσess(Xt) > infσess(Xµ) = 0.<br />

Therefore, by using (72), we obtain a one-to-one correspondence<br />

σ(ξ)∩(−∞,µ) ↔ σ(Xµ)∩(−∞,0). (73)<br />

9. From the inequality µ 2 (H −K) −1 +H −K ≥ 2µ we get<br />

Xµ = H +K − µ2<br />

H −K<br />

≤ 2(H −µ).<br />

Moreover, note that infσess(Xµ) = infσess(H −µ) = 0. Therefore, the number<br />

of negative eigenvalues (with multiplicity) of Xµ is not less than the<br />

number of negative eigenvalues (with multiplicity) of (H −µ) .<br />

In particular, if (H − µ) has infinitely many negative eigenvalues, then<br />

Xµ has infinitely many negative eigenvalues. By (73), we see that ξ has<br />

infinitely many eigenvalues below its essential spectrum. Consequently, H<br />

has infinitely many eigenvalues below its essential spectrum.<br />

10. Now we assume furthermore that K ≥ 0. Then we get the inequality<br />

Xµ = H +K − µ2 µ2<br />

≥ H −K −<br />

H −K H −K .<br />

Moreover, note that<br />

�<br />

infσess(Xµ) = infσess H −K − µ2<br />

�<br />

= 0.<br />

H −K<br />

Thus, if H − K has finitely many eigenvalues below µ, then Xt also has<br />

finitely many negative eigenvalues. By (73), ξ has finitely many eigenvalues<br />

below its essential spectrum. Consequently, H has the same property. �<br />

Appendix B. Localization of band operators on F+<br />

In this appendix we prove the localization in Proposition 22.<br />

Proof of Proposition 22. Using the IMS-identity<br />

A = fMAfM +gMAgM + 1<br />

2 ([fM,[fM,A]]+[gM,[gM,A]])

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