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Pensar en C++ (Volumen 1) - Grupo ARCO
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“Volum<strong>en</strong>1” — 2012/1/12 — 13:52 — page 155 — #193<br />
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4.3. El objeto básico<br />
stringStash.initialize(sizeof(char) * bufsize);<br />
ifstream in("CppLibTest.cpp");<br />
assure(in, "CppLibTest.cpp");<br />
string line;<br />
while(getline(in, line))<br />
stringStash.add(line.c_str());<br />
int k = 0;<br />
char* cp;<br />
while((cp =(char*)stringStash.fetch(k++)) != 0)<br />
cout
✐ ✐ ✐ “Volum<strong>en</strong>1” — 2012/1/12 — 13:52 — page 154 — #192 ✐ Capítulo 4. Abstracción de Datos y no habrá ningún tipo de queja por parte de compilador. Sin embargo, <strong>en</strong> <strong>C++</strong>, lo anterior no está permitido. ¿Por qué Porque C no es tan estricto con los tipos de datos y permite asignar un puntero sin un tipo específico a un puntero de un tipo bi<strong>en</strong> determinado. No así <strong>C++</strong>, <strong>en</strong> el cual la verificación de tipos es crítica y el compilador se det<strong>en</strong>drá quejándose <strong>en</strong> cualquier conflicto de tipos. Esto siempre ha sido importante, pero es especialm<strong>en</strong>te importante <strong>en</strong> <strong>C++</strong> ya que d<strong>en</strong>tro de las estructuras puede hacer métodos. Si <strong>en</strong> <strong>C++</strong> estuviera permitido pasar punteros a estructuras con impunidad <strong>en</strong> cuanto a conflicto de tipos, ¡podría terminar llamando a un método de una estructura <strong>en</strong> la cual no existiera dicha función miembro! Una verdadera fórmula para el desastre. Así, mi<strong>en</strong>tras <strong>C++</strong> sí deja asignar cualquier puntero a un void * (<strong>en</strong> realidad este es el propósito original del puntero a void: que sea sufici<strong>en</strong>tem<strong>en</strong>te largo como para apuntar a cualquier tipo) no permite asignar un void * a cualquier otro tipo de puntero. Para ello se requiere un molde que le indique tanto al lector como al compilador que realm<strong>en</strong>te quiere tratarlo como el puntero destino. Y esto nos lleva a discutir un asunto interesante. Uno de los objetivos importantes de <strong>C++</strong> es poder compilar la mayor cantidad posible de código C para así, permitir una fácil transición al nuevo l<strong>en</strong>guaje. Sin embargo, eso no significa, como se ha visto que cualquier segm<strong>en</strong>to de código que sea válido <strong>en</strong> C, será permitido automáticam<strong>en</strong>te <strong>en</strong> <strong>C++</strong>. Hay varias cosas que un compilador de C permite hacer que son pot<strong>en</strong>cialm<strong>en</strong>te peligrosas y prop<strong>en</strong>sas a g<strong>en</strong>erar errores (verá ejemplos de a lo largo de libro). El compilador de <strong>C++</strong> g<strong>en</strong>era errores y avisos <strong>en</strong> este tipo de situaciones y como verá eso es más una v<strong>en</strong>taja que un obstáculo a pesar de su naturaleza restrictiva. ¡De hecho, exist<strong>en</strong> muchas situaciones <strong>en</strong> las cuales tratará de detectar sin éxito un error <strong>en</strong> C y cuando recompiles el programa con un compilador de <strong>C++</strong> éste avisa exactam<strong>en</strong>te de la causa del problema!. En C, muy a m<strong>en</strong>udo ocurre que para que un programa funcione correctam<strong>en</strong>te, además de compilarlo, luego debe hacer que ande. ¡En <strong>C++</strong>, por el contrario, verá que muchas veces si un programa compila correctam<strong>en</strong>te es probable que funcione bi<strong>en</strong>! Esto se debe a que este último l<strong>en</strong>guaje es mucho más estricto respecto a la comprobación de tipos. En el sigui<strong>en</strong>te programa de prueba podrá apreciar cosas nuevas con respecto a cómo se utiliza la nueva versión de la Stash: //: C04:CppLibTest.cpp //{L} CppLib // Test of <strong>C++</strong> library #include "CppLib.h" #include "../require.h" #include #include #include using namespace std; int main() { Stash intStash; intStash.initialize(sizeof(int)); for(int i = 0; i < 100; i++) intStash.add(&i); for(int j = 0; j < intStash.count(); j++) cout
✐ ✐ ✐ “Volum<strong>en</strong>1” — 2012/1/12 — 13:52 — page 155 — #193 ✐ 4.3. El objeto básico stringStash.initialize(sizeof(char) * bufsize); ifstream in("CppLibTest.cpp"); assure(in, "CppLibTest.cpp"); string line; while(getline(in, line)) stringStash.add(line.c_str()); int k = 0; char* cp; while((cp =(char*)stringStash.fetch(k++)) != 0) cout
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