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La Phosphorylation oxydative - IBMC

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Oxydation du FADH 2<br />

a) 1/2 O 2 + 2 H + + 2 e - H 2 O<br />

b) FAD + 2 H + + 2 e - FADH 2<br />

E’ 0 = +0,82 V<br />

E’ 0 = -0,1 V<br />

a -b = 1/2 O 2 + FADH 2<br />

H 2 O + FAD<br />

ΔE’ 0 = +0,82 V + 0,10 V = 0,92 V<br />

ΔG°’ = -2 × 23,062 × 0,92<br />

= - 42,4 kcal / mole

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