13.07.2015 Views

Chapitre 10 Rotation d'un corps rigide

Chapitre 10 Rotation d'un corps rigide

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a = aa =ac+ aa2t+ a2c= 32,6 mst2#22) Configuration de charges ponctuelles :Massem 1kgPosition3 m,1m= 1 ( )= 2 ( − 2m,2m)= 3 ( 1m,− 1m)= 4 ( 2m,−1m)m 2kgm 4kgm 4kg− Masses ponctuelles2,52m 21,5m 11y[m]0,50-3 -2 -1 0 1 2 3 4-0,5m 3-1m 4-1,5x[m]4222222a) Ix= ∑ miri= m1y1+ m2y2+ m3y3+ m4y4= 16,0kg mi=14222222b) I m r = m x + m x + m x + m x 36,0kg m= ∑y i i 1 1 2 2 3 3 4 4=i=12c) I = I + I 52,0kg mz x y=11

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