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c) La vitesse angulaire moyenne :θ = −1radd)e)θω( t=1s)( t=2s)moyenne#13) Roue :r = 0,2mθ = 00= 16 radθ = 90⋅2πrad∆θ17 rad= =∆t1s120⋅2πω rad0= = 4πrad60 s sω = ?α = ?t = 60s12= 17,0 rads2a) θ = θ + ω t + α t ⇒ α = −0,20 0<strong>10</strong>5radsb) Du début jusqu’à la fin :2 2ω = ω + 2α∆θ20 = ω + 2α∆θ⇒00∆θ= 752radNombre de tours supplémentaires à 90 :752rad − 90⋅ 2πrad = 186 rad ⇒ 29,7tours( )Distance supplémentaire :d = 29,7tours ⋅ 2πr = 37,3m9