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• Dans l’équation (4) :⎛ 1 ⎞(4) a ⎜ R M + R M ⎟ = R Mg sinθ⎝ 2 ⎠3 2 a = g sinθ⇒ a = g sinθi23b) De l’équation (3) :aR fs= Iα= I ⇒Retfs= µ N = µ Mg cosθs(5) = (6) :1Mg sinθ= µsMg cosθ3sfsI a= =2R(6)⇒12MRR222 1g sinθ= Mg sinθ3 31µs= tanθ3(5)#60) Une tige :M = 0,04kgL = 1mI = ICMθ = 20°+ M11222( 0,15m) = M L + M ( 0,15m)2= 0,00423kg m2+CMaxe 20 °r P = Mg∑ τ = τ = r × P = r Mg sin=P( 90° − 20°) = Iα⇒ α 13,1 rad2s27
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