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c) À t = 2s:a 0,480 mt= α r =2s 2a r 7,26mc= ω =s2#6) Démonstration :a ta = ac+ ata ca ( ) 2( 2a = α r + ω r )2 4a = r +αω2#7) Roue :θ = 00θ = ?50⋅2πω rad0=60 sω = 2ωα = 0,5 radst = ?02Le problème doit être divisé en 2 étapes :• Moteur est accéléré :ω = ω + α t2ω= ω + α t000⇒ t = <strong>10</strong>,5s1 2θ = θ0+ ω0t+ α t2⇒ θ = 82,4 rad7