17.12.2016 Views

Brug van Wheatstone

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<strong>Brug</strong> in evenwicht – Deelspanningen<br />

• 1 e arm = spanningsdeler 1<br />

U<br />

A<br />

U<br />

bron<br />

R2<br />

20k<br />

9<br />

R1<br />

R2<br />

10k 20k<br />

• 2 e arm = spanningsdeler 2<br />

6V<br />

R1<br />

R2<br />

U A<br />

U B<br />

U<br />

B<br />

U<br />

bron<br />

R4<br />

12k<br />

9<br />

6V<br />

R3<br />

R4<br />

6k 12k<br />

• Gelijkstellen <strong>van</strong> U A en U B geeft<br />

R 1 R3<br />

2<br />

R2<br />

R4<br />

ofwel<br />

R1<br />

R4<br />

R3<br />

R<br />

R3<br />

R4<br />

Product overstaande weerstanden gelijk<br />

KHLim-Lerarenopleiding Vakstudie Elektriciteit - René Peeters 6

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