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Curso <strong>de</strong> linguagem matemática – Professor Renato TiãoResolver as <strong>equações</strong> a seguir, no universo dos números reais.Primeiro bloco:a) 2x − 6 = 0b) 3x + 8 = 0c) −2x + 5 = 0d) −3x − 3 = 0e) 4x – 8 = 0f) –5x + 20 = 0g) 10x + 2 = 0h) –x – 5 = 0i) 0x + 7 = 0j) 0x = 0Segundo bloco:a) x 2 − 7x = 0b) x 2 + 9x = 0c) x 2 − 25 = 0d) x 2 + 16 = 0e) x 2 + 9 = 0f) x 2 = 4xg) x 2 – 7 = 0h) x 2 – 1 = 0i) x 2 + πx = 0j) 2x 2 + 7x = 0Terceiro bloco:a) 6x 2 − 10x + 4 = 0b) 4x 2 + 4x + 1 = 0c) 3x 2 + 2x + 7 = 0d) x 2 – 2x – 2 = 0e) x 2 + x – 1 = 0f) x 2 −(π+2)x + 2π = 0g) x 4 + 5x 2 + 4 = 0h) x 4 – 3x 2 – 4 = 0i) x 4 – 13x 2 +36 = 0j) x 6 + 9x 3 +8 = 0Quarto bloco:a) 3(x + 5) = 3x + 2b) 5(6 – 4x) + 2(10x – 15) = 0c) (x +2)(3x +5) = (x +2)(1−2x)d) 2x 2 + 5x + 6 = x 2 + x(x+1)Quinto bloco:a) x+1 = xxb) c)x x+2 5x+ =3 4 63(x+2) - xx =2d) 7x - x =x10 5 21 1 3x -1e) + =2x x+1 x +xf)x xx+ =5+x -5 x -52⎛ 1⎞ ⎛ 1⎞g)8 ⎜x - ⎟ - 42⎜x - ⎟+45= 0⎝ x ⎠ ⎝ x ⎠Sexto bloco:a)b)5 4 3 2x +10x +25x +8x +80x+200 = 06 5 4 3 2x -5x -13x +65x +36x -180x = 0Sétimo bloco:a) x - 6 = 15 - 2xb) 3- x = x + 3c) x - x + 3 =3d) x + x + 3 =3e) x - x + 3 = 3f) 5 x = x+6


Curso <strong>de</strong> linguagem matemática – Professor Renato TiãoOitavo bloco:a) x = 2b) x -5 = 2c) x+3 = 0d)2x -5x = -1e) 2x+8 = 6f)25x = x -6g) x+3 - 5 = xh) x+3 = x -5i) x -1 + x -7 = 10j) x -1 + x -7 = 6k) x -1 + x -7 = 4l) 2x -3 = 3-2xm) 2x+ x -3 = 12Décimo bloco:a) log x = 37b) logx -1=2c) log(x -1) = 2d) log (1+2x) = 23e) log (25- x ) = 42f) log (x +100) = 352g) 6+3log (6-3x) = 04100h) log (7+ ) = 52 x28i) 7- = 5logx8j) = 27 - log(x+2)k)log 0,25= -1xl) log =x ( 2 2)3m)log 5=5xn)log (5x) =5xa)b)c)x4 = 0,125x x-27 +7 =50x8 + 256 = 02xd) 2 -8 ⋅2 +12= 0xe) 25 +125= 30 ⋅5xf) 49 +50 ⋅7 +49 = 0g)h)i)j)xxx 5 -x2 +2 =18x - 3x =12 x-2(x +4x+4) = 1x x-1 x-24 -15 = 4Nono bloco:xo)log (8x -7) = 2xp) log(x − 1)(5x -9) = 21q) log (1+ ) = 1x xr)s)2logx - 4logx+3= 02(logx) - 4logx+3= 0t) log (12-2 ) = 2x2u) log10 x + 2logx10 = 3v) log2 x −log 2(x −3) =2xw) logx2=log x4x) 2log2(1+ 2x) − log2( 2x) =3y) log (x-2)-log x =142

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