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MATEMATIKA 1 skripta studij: Biotehnologija i Prehrambena ... - PBF

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Ako je a ≠ 3 sustav je nesuglasan, a ako je a = 3 sustav je suglasan i<br />

neodreden.<br />

[ ]<br />

2 3 −1<br />

Zadatak 33 RješitematričnujednadžbuAX = B akoje A = , B =<br />

3 −2 1<br />

[ ]<br />

1<br />

.<br />

2<br />

Rješenje:<br />

[<br />

2 3 −1<br />

3 −2 1<br />

] ⎡ ⎤<br />

x 1<br />

[<br />

⎢ ⎢⎣ x 2<br />

⎥ 1<br />

⎦ = 2<br />

x 3<br />

]<br />

⇔ 2x 1 + 3x 2 − x 3 = 1<br />

3x 1 − 2x 2 + x 3 = 2<br />

⇒<br />

[ ] [ ] [<br />

2 3 −1 | 1 5 1 0 | 3 5 1 0 | 3<br />

∼ ∼<br />

3 −2 1 | 2 3 −2 1 | 2 13 0 1 | 8<br />

⎡ ⎤ ⎡ ⎤ ⎡ ⎤<br />

x 1 = t x 1 0 1<br />

x 2 = 3−5t ⇒ ⎢<br />

⎣ x 2<br />

⎥<br />

⎦ = ⎢<br />

⎣ 3 ⎥<br />

⎦ +t ⎢<br />

⎣ −5 ⎥<br />

⎦ , t ∈ R.<br />

x 3 = 8−13t x 3 8 −13<br />

]<br />

Zadatak [ 34]<br />

Rješite matričnu jednadžbu XA 8 + A ∗ = XA − A 11 ako je<br />

0 1<br />

A = .<br />

1 0<br />

Rješenje:<br />

[ ]<br />

X(A 8 −A) = −A ∗ −A 11 , A ∗ 0 −1<br />

= ,<br />

−1 0<br />

[ ][ ] [ ]<br />

0 1 0 1 1 0<br />

A 2 = = = I za parne potencije<br />

1 0 1 0 0 1<br />

[ ][ ] [ ]<br />

1 0 0 1 0 1<br />

A 3 = = = A za neparne potencije<br />

0 1 1 0 1 0<br />

[ ] [ ] [ ]<br />

1 0 0 1<br />

⇒ A 8 1 −1<br />

−A = I −A = − =<br />

0 1 1 0 −1 1<br />

28

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