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JavaPsi - Simulating and Visualizing Quantum Mechanics (english)

JavaPsi - Simulating and Visualizing Quantum Mechanics (english)

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3 SOLVING SCHRÖDINGER’S EQUATION 10<br />

E = 0 cannot be an energy eigenwert, i.e. the minimum possible energy E0<br />

has to be greater than 0.<br />

A further rather interesting effect can be seen at the wave function in<br />

figure 2. Namely, the probability |ψ(x)| 2 is greater than 0 even if the total<br />

energy E is lower than the potential energy V (x). This at the first<br />

glance very strange behavior which cannot be explained classically is basically<br />

caused by the fact that quantum mechanics postulates continuity of the<br />

wave function. In a similar way one observes the tunnel effect (c.f. section<br />

3.2.4) at potential walls.<br />

3.2 One-dimensional, time-dependent case<br />

3.2.1 Schrödinger’s equation<br />

Schrödinger’s equation in the one-dimensional, time-dependent case is<br />

<br />

− 2<br />

2m ∇2 <br />

∂Ψ(x, t)<br />

+ V (x, t) Ψ(x, t) = i<br />

∂t<br />

with complex-valued wavefunction Ψ(x, t).<br />

3.2.2 Algorithm<br />

To solve the one-dimensional, time-dependent Schrödinger equation the<br />

so-called Goldberg-Schey-Schwartz-algorithm is used. 15 The desired complexvalued<br />

wave function Ψ(x, t) is formatted in a grid:<br />

x = jɛ, j = 0, 1, . . . J,<br />

t = nδ, n = 0, 1, . . . ,<br />

Ψ(x, t) ∼ = Ψ n j . (3.20)<br />

Now we look for an iteration which calculates from the inital wave function<br />

Ψ 0 j<br />

<strong>and</strong> the potential V n<br />

j the whole wave function Ψn j :<br />

Iteration for Ψ n j :<br />

1. e1 = 2 + 2∆t 2 V1 −<br />

ej = 2 + 2∆t 2 Vj −<br />

2. Ω n j = −Ψn j+1 +<br />

x = j∆t, j = 0, 1, . . . J,<br />

t = n∆t, n = 0, 1, . . .<br />

4i ∆t2<br />

∆t<br />

4i ∆t2<br />

∆t<br />

Ψ(x, t) ∼ = Ψ n j<br />

1 − , j = 2 . . . J<br />

ej−1<br />

4i ∆t 2<br />

∆t + 2∆t2 Vj + 2<br />

3. f n 1 = Ωn1 <strong>and</strong> f n j = Ωnj + f n j−1<br />

, j = 2, . . . J<br />

ej−1<br />

4. Ψ n+1<br />

J−1 = − f n J−1<br />

eJ−1 ,<br />

Ψ n+1<br />

j<br />

Ψn+1<br />

j+1<br />

= −f n j<br />

, j = J − 2 . . . 1<br />

ej<br />

5. n = n + 1 <strong>and</strong> go to 1.<br />

15 For derivation see [5] p. 103ff.<br />

<br />

Ψn j − Ψnj−1 , j = 0 . . . J

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