Gas Laws

c. Al should be limiting because
you would not want aluminum
metal remaining in the drain.
11. a. 0.0422 mol Cu; 0.169 mol HNO 3
b. Cu is in excess
c. 3.32 g H 2O
12. a. 2.90 mol NO;
4.35 mol H 2O
b. NH 3 is limiting
c. NH 3 is limiting; 1.53 10 3 kg
NO
13. 565 g CH 3CHO;
29 g CH 3CH 2OH remains
14. 630 g HBr
15. 11.3 g SO 2
16. a. 18.4 g Tb
b. 2.4 g TbF 3
10 Percentage Yield
1. a. 64.3% yield
b. 58.0% yield
c. 69.5% yield
d. CH 3CH 2OH is limiting; 79%
yield
2. a. 69.5% yield
b. 79.0% yield
c. 48% yield
d. 85% yield
3. a. 59% yield
b. 81.0% yield
c. 2.3 10 5 mol P
4. a. 91.8% yield
b. 0.0148 mol W
c. 16.1 g WO 3
5. a. 86.8% yield
b. 92.2% yield
c. 2.97 10 4 kg CS 2 ;
4.39 10 4 kg S 2Cl 2
6. a. 81% yield
b. 2.0 10 2 g N 2O 5
7. 80.1% yield
8. a. 95% yield
b. 9.10 10 2 g Au
c. 9 10 4 kg ore
9. a. 87.5% yield
b. 0.25 g CO
10. a. 71% yield
b. 26 metric tons
c. 47.8 g NaCl
d. 500 kg per hour NaOH
11. a. 2Mg O 2 : 2MgO
b. 87.7% yield
c. 3Mg N 2 : Mg 3N 2
d. 56% yield
12. a. 80.% yield
b. 66.2% yield
c. 57.1% yield
13. 2C 3H 6(g) 2NH 3(g) 3O 2(g) :
2C 3H 3N(g) 6H 2O(g)
91.0% yield
14. a. CO 2H 2 : CH 3OH
3.41 10 3 kg
b. 91.5% yield
15. 96.9% yield
16. 6CO 2 6H 2O : C 6H 12O 6 6O 2
6.32 10 3 g O 2
17. 27.6 kg CaO
11 Gas Laws
1. a. 105 kPa
b. 5.0 mL
c. 42.4 kPa
d. 6.78 10 3 dm 3
e. 1.24 atm
f. 1.5 m 3
2. 8.0 m 3
3. 0.0258 atm
4. 8.01 10 2 dm 3
5. a. 234 K
b. 1.2 dm 3
c. 269.17°C
d. 8.10 10 2 L
e. 487 cm 3
f. 67.9 m 3
6. 1.45 cm 3
7. 40.°C
8. a. 208.6°C
b. 5.5 kPa
c. 2.61 atm
d. 297°C
e. 35.6 atm
f. 39 K
9. 0.899 atm
10. 2.23 atm
11. 7.98 K
12. a. 2.02 L
b. 75.8 kPa
c. 110 K
d. 4.69 10 3 mm 3
e. 72°C
f. 2.25 atm
13. 379 cm 3
14. 98 kPa
15. 1.00 atm; use Boyle’s law to find the
pressure of each gas in the whole
Answer Key 291