Gas Laws
Gas Laws
Gas Laws
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SAMPLE PROBLEM 3<br />
A cylinder of gas has a pressure of 4.40 atm at 25°C. At what<br />
temperature in °C will it reach a pressure of 6.50 atm?<br />
SOLUTION<br />
1. ANALYZE<br />
• What is given in the the original pressure and temperaproblem?<br />
ture of the gas in the cylinder, and<br />
the new pressure of the sample<br />
• What are you asked to find? the temperature at which the gas<br />
reaches the specified pressure<br />
Items Data<br />
Original pressure, P 1<br />
Original temperature, t 1<br />
Original Kelvin temperature, T 1<br />
New pressure, P 2<br />
New temperature, t 2<br />
New Kelvin temperature, T 2<br />
4.40 atm<br />
25°C<br />
(25 273) K 298 K<br />
6.50 atm<br />
2. PLAN<br />
• What steps are needed to Rearrange the Gay-Lussac’s law<br />
calculate the new tempera- equation to solve for T 2, substitute<br />
ture of the gas? known quantities, and calculate.<br />
1<br />
P1 P2 <br />
T1 T2 to solve for T2 , divide<br />
both sides of the equation<br />
by P2 and invert the<br />
equality to isolate T2 insert data and solve for T2 ?°C<br />
? K<br />
T 1 P 2<br />
P 1<br />
2<br />
T 2<br />
3. COMPUTE<br />
Substitute data for the terms of the equation, and compute the result.<br />
T 2 T 1P 2<br />
P 1<br />
<br />
298 K 6.50 atm<br />
4.40 atm<br />
440. K<br />
Convert back to °C.<br />
440. K (440. 273)°C 167°C<br />
4. EVALUATE<br />
• Are the units correct? Yes; units canceled to give Kelvin<br />
temperature, which was converted<br />
to °C.<br />
<strong>Gas</strong> <strong>Laws</strong> 125
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