Gas Laws
Gas Laws
Gas Laws
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PRACTICE<br />
In each of the following problems, assume that the pressure and molar<br />
quantity of gas do not change.<br />
1. Calculate the unknown quantity in each of the following measurements<br />
of gases.<br />
V 1 T 1 V 2 T 2<br />
a. 40.0 mL 280. K ? mL 350. K<br />
b. 0.606 L 300. K 0.404 L ? K<br />
c. ? mL 292 K 250. mL 365 K<br />
d. 100. mL ? K 125 mL 305 K<br />
e. 0.0024 L 22°C ? L 14°C<br />
ans: 50.0 mL<br />
ans: 200. K<br />
ans: 200. mL<br />
ans: 244 K<br />
ans: 0.0021 L<br />
2. A balloon full of air has a volume of 2.75 L<br />
at a temperature of 18°C. What is the balloon’s<br />
volume at 45°C? ans: 3.01 L<br />
3. A sample of argon has a volume of 0.43 mL at 24°C.<br />
At what temperature in degrees Celsius will it have<br />
a volume of 0.57 mL? ans: 121°C<br />
GAY-LUSSAC’S LAW<br />
You may have noticed a warning on an aerosol spray can that says something<br />
similar to Do not incinerate! Do not expose to temperatures greater<br />
than 140°F! Warnings such as this appear because the pressure of a confined<br />
gas increases with increasing temperature. If the temperature of the<br />
can increases enough, the can will explode because of the pressure that<br />
builds up inside of it.<br />
The relationship between the pressure and temperature of a gas is described<br />
by Gay-Lussac’s law. Gay-Lussac’s law states that the pressure of<br />
a sample of gas is directly proportional to the absolute temperature when<br />
volume remains constant. Gay-Lussac’s law can be expressed as follows.<br />
P T and P<br />
T<br />
k, or P kT<br />
According to Gay-Lussac’s law, when the temperature of a sample of<br />
gas increases, the pressure of the gas increases by the same factor. Therefore,<br />
doubling the temperature of a gas will double its pressure. Reducing<br />
the temperature of a gas to 75% of its original value will also reduce the<br />
pressure to 75% of its original value.<br />
<strong>Gas</strong> <strong>Laws</strong> 123