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Answers to Selected Problems

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we learn that p J = $2,000 and p A = $2,500.<br />

As the chapter shows, the elasticities of demand<br />

are ε J = p/(MC - p) = 2,000/(500 - 2,000) = - 4<br />

3<br />

and ε A = 2,500/(500 - 2,500) = - 5<br />

4<br />

tion 12.9, we find that<br />

p J<br />

p A<br />

= 2,000<br />

2,500<br />

5<br />

1 + 1/1 - 42<br />

= 0.8 =<br />

1 + 1/1 - 4<br />

. Using Equa-<br />

32 = 1 + 1/εA .<br />

1 + 1/εJ The profit in Japan is (pJ - m)QJ = ($2,000 -<br />

$500) * 3,000 = $4.5 million, and the U.S. profit is<br />

$4 million. The deadweight loss is greater in Japan,<br />

$2.25 million 1 = 1<br />

2 * $1,500 * 3,0002, than in the<br />

United States, $2 million 1 = 1<br />

2 * $2,000 * 2,0002.<br />

3.6 By differentiating, we find that the American marginal<br />

revenue function is MRA = 100 - 2QA , and<br />

the Japanese one is MRJ = 80 - 4QJ. To determine<br />

how many units <strong>to</strong> sell in the United States, the<br />

monopoly sets its American marginal revenue equal<br />

<strong>to</strong> its marginal cost, MRA = 100 - 2QA = 20,<br />

and solves for the optimal quantity, QA = 40 units.<br />

Similarly, because MRJ = 80 - 4QJ = 20, the optimal<br />

quantity is QJ = 15 units in Japan. Substituting<br />

QA = 40 in<strong>to</strong> the American demand function,<br />

we find that pA = 100 - 40 = $60. Similarly, substituting<br />

QJ = 15 units in<strong>to</strong> the Japanese demand<br />

function, we learn that pJ = 80 - (2 * 15) = $50.<br />

Thus, the price-discriminating monopoly charges<br />

20% more in the United States than in Japan. We<br />

can also show this result using elasticities. Because<br />

dQA /dpA = -1 the elasticity of demand is εA =<br />

-pA /QA in the United States and εJ = - 1<br />

2 PJ /QJ in<br />

Japan. In the equilibrium, εA = -60/40 = -3/2<br />

and εJ = -50/(2 * 15) = -5/3. As Equation<br />

12.9 shows, the ratio of the prices depends on the<br />

relative elasticities of demand: pA /pJ = 60/50 =<br />

(1 + 1/εJ )/(1 + 1/εA ) = (1 - 3/5)/(1 - 2/3) = 6/5.<br />

3.8 From the problem, we know that the profitmaximizing<br />

Chinese price is p = 3 and that the<br />

quantity is Q = 0.1 (million). The marginal cost<br />

is m = 1. Using Equation 11.11, (pC - m)/pC =<br />

(3 - 1)/3 = -1/εC , so εC = -3/2. If the Chinese<br />

inverse demand curve is p = a - bQ, then<br />

the corresponding marginal revenue curve is<br />

MR = a - 2bQ. Warner maximizes its profit<br />

where MR = a - 2bQ = m = 1, so its optimal<br />

Q = (a - 1)/(2b). Substituting this expression<br />

in<strong>to</strong> the inverse demand curve, we find that its<br />

optimal p = (a + 1)/2 = 3, or a = 5. Substituting<br />

that result in<strong>to</strong> the output equation, we have<br />

Q = (5 - 1)/(2b) = 0.1 (million). Thus, b = 20,<br />

the inverse demand function is p = 5 - 20Q, and<br />

the marginal revenue function is MR = 5 - 40Q.<br />

Using this information, you can draw a figure<br />

similar <strong>to</strong> Figure 12.3.<br />

<strong>Answers</strong> <strong>to</strong> <strong>Selected</strong> <strong>Problems</strong><br />

E-45<br />

3.11 If a monopoly manufacturer can price discriminate,<br />

its price is p i = m/(1 + 1/ε i ) in Country i, i = 1, 2. If<br />

the monopoly cannot price discriminate, it charges<br />

everyone the same price. Its <strong>to</strong>tal demand is Q =<br />

Q 1 + Q 2 = n 1 p ε 1 + n 2 p ε 2. Differentiating with<br />

respect <strong>to</strong> p, we obtain dQ/dp = ε 1 Q 1 /p + ε 2 Q 2 /p.<br />

Multiplying through by p/Q, we learn that the<br />

weighted sum of the two groups’ elasticities is<br />

ε = s 1 ε 1 + s 2 ε 2 , where s i = Q i /Q. Thus, a profitmaximizing,<br />

single-price monopoly charges p =<br />

m/(1 + 1/ε).<br />

Chapter 13<br />

1.1 The payoff matrix in this prisoners’ dilemma game is<br />

Larry<br />

Squeal<br />

Silent<br />

–2<br />

–5<br />

Duncan<br />

Squeal Silent<br />

–2 –5<br />

If Duncan stays silent, Larry gets 0 if he squeals and<br />

-1 (a year in jail) if he stays silent. If Duncan confesses,<br />

Larry gets -2 if he squeals and -5 if he does<br />

not. Thus, Larry is better off squealing in either<br />

case, so squealing is his dominant strategy. By the<br />

same reasoning, squealing is also Duncan’s dominant<br />

strategy. As a result, the Nash equilibrium is<br />

for both <strong>to</strong> confess.<br />

1.3 No strategies are dominant, so we use the bestresponse<br />

approach <strong>to</strong> determine the pure-strategy<br />

Nash equilibria. First, identify each firm’s best<br />

responses given each of the other firms’ strategies<br />

(as we did in Solved Problem 13.1). This game has<br />

two Nash equilibria: (a) Firm 1 medium and Firm 2<br />

low, and (b) Firm 1 low and Firm 2 medium.<br />

1.8 Let the probability that a firm sets a low price be<br />

θ1 for Firm 1 and θ2 for Firm 2. If the firms choose<br />

their prices independently, then θ1θ2 is the probability<br />

that both set a low price, (1 - θ1 )(1 - θ2 ) is the<br />

probability that both set a high price, θ1 (1 - θ2 )<br />

is the probability that Firm 1 prices low and Firm 2<br />

prices high, and (1 - θ1 )θ2 is the probability that Firm<br />

1 prices high and Firm 2 prices low. Firm 2’s expected<br />

payoff is E(π2 ) = 2θ1θ2 + (0)θ1 (1 - θ2 ) + (1 - θ1 )θ2 + 6(1 - θ1 )(1 - θ2 ) = (6 - 6θ1 ) - (5 - 7θ1 )θ2 .<br />

Similarly, Firm 1’s expected payoff is E(π1 ) =<br />

(0)θ1θ2 + 7θ1 (1 - θ2 ) + 2(1 - θ1 )θ2 + 6(1 - θ1 )(1 - θ2 )<br />

= (6 - 4θ2 ) - (1 - 3θ2 )θ1 . Each firm forms a<br />

0<br />

0 –1<br />

–1

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