20.12.2013 Views

booklet format - inaf iasf bologna

booklet format - inaf iasf bologna

booklet format - inaf iasf bologna

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

Temporal Data Analysis A.A. 2011/2012<br />

Figure 2.3: Fourier decomposition of a musical signal: on the left the harmonic content (that is<br />

the valued of the Fourier coefficients) for a note produced by a flute. On the left the same note<br />

as played by a violin. On the abscissa we list the Fourier frequency index k<br />

2.1.3 Fourier Series and Music<br />

While listening to music, we are able to clearly distinguish the sound produced by different<br />

instruments. The sound coming from a flute is quite different from the sound coming from<br />

a violin, even if they play the same note (that is, they produce a sound wave with the same<br />

frequency).<br />

In musical terms, this difference is called timbre and it can be easily explained in terms of<br />

Fourier decomposition of the signal. Indeed, if we apply Eq. (2.1) and extract the Fourier<br />

coefficients for the two instruments we will obtain something like shown in Figure 2.3: the<br />

harmonic content is quite different. For the violin we have that all the first eight Fourier<br />

frequencies are present. On the other hand, for the flute only the first two are strong, while the<br />

others are much smaller. That’s what makes the sound of a violin more complex (and therefore<br />

more expressive) with respect to the sound of a flute.<br />

In general terms, we call pitch of a sound the “perceived” frequency of a musical note, and it is<br />

related to amount of Fourier frequencies we (that is, our ear) are able to distinguish.<br />

2.1.4 Fourier Series in Complex Notation<br />

In (2.1) the index k starts from 0, meaning that we will rule out negative frequencies in our<br />

Fourier series. The cosine terms didn’t have a problem with negative frequencies. The sign of<br />

the cosine argument doesn’t matter anyway, so we would be able to go halves as far as the<br />

spectral intensity at the positive frequency kω was concerned: −kω and kω would get equal<br />

parts, as shown in Figure 2.4. As frequency ω = 0 (a frequency as good as any other frequency<br />

ω ≠ 0) has no “brother”, it will not have to go halves. A change of sign for the sine-terms<br />

arguments would result in a change of sign for the corresponding series term. The splitting of<br />

spectral intensity like “between brothers” (equal parts of −ω k and +ω k now will have to be like<br />

16 M.Orlandini

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!