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Function Spaces as Dirichlet Spaces (About a Paper by Maz'ya and ...

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8 N. Jacob <strong>and</strong> R. L. Schilling<br />

Proof. Denote <strong>by</strong> T −y the translation operator T −y u(x) := u(x + y). Since<br />

|e it − 1| 2 = 2(1 − cos t), t ∈ R, we find using Plancherel’s Theorem<br />

∫∫<br />

1<br />

|u(x + y) − u(x)| 2 dx ν(dy)<br />

2 R n ×(R n \{0})<br />

= 1 ∫<br />

‖T −y u − u‖ 2 L<br />

2<br />

ν(dy)<br />

2 R n \{0}<br />

= 1 ∫<br />

∥ (T−y u)̂ − û ∥ 2 ν(dy)<br />

2 R n L 2 \{0}<br />

= 1 ∫ ( ∫<br />

)<br />

|û(ξ)e −iyξ − û(ξ)| 2 dξ ν(dy)<br />

2 R n \{0} R n<br />

= 1 ∫<br />

)<br />

(|û(ξ)|<br />

2<br />

∫R 2 |e −iyξ − 1| 2 ν(dy) dξ<br />

n R n \{0}<br />

∫<br />

)<br />

=<br />

(|û(ξ)|<br />

∫R 2 (1 − cos yξ) ν(dy) dξ<br />

n R n \{0}<br />

∫<br />

= |û(ξ)| 2 ψ(ξ) dξ.<br />

R n<br />

If ψ(ξ) = f(|ξ| 2 ), we see from Lemma 2.1 that ν(dy) = m(|y| 2 ) dy with a<br />

completely monotone density m(r) <strong>and</strong><br />

∫<br />

|û(ξ)| 2 f(|ξ| 2 ) dξ = 1 ∫∫<br />

|u(x + y) − u(x)| 2 m(|y| 2 ) dy dx. (16)<br />

R 2<br />

n R n ×R n<br />

Up to notational changes, the following result is proved in Maz’ya <strong>and</strong><br />

Nagel [18].<br />

Lemma 3.2. Let g j<br />

functions such that<br />

: [0, ∞] → [0, ∞], 1 j n, be monotone incre<strong>as</strong>ing<br />

∫ 1<br />

0<br />

g j (s)<br />

s<br />

ds +<br />

∫ ∞<br />

1<br />

g j (s)<br />

s 2 ds < ∞. (17)<br />

Then µ j (|t|) := ∫ |t|<br />

0<br />

n∑<br />

( ∫∫<br />

j=1<br />

∫ ∞<br />

g<br />

r j (s)/s ds dr is well-defined <strong>and</strong><br />

( 1<br />

|u(x + t j e j ) − u(x)| 2 g j<br />

R 1 ×R t 2 n j<br />

( ∫<br />

n∑<br />

∼ |û(ξ)| 2 µ j (|ξ j | 2 ) dξ<br />

R n<br />

j=1<br />

) ) 1<br />

dx dtj<br />

2<br />

|t j |<br />

) 1<br />

2<br />

(18)<br />

are equivalent seminorms on S(R n ).

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