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Network Coding and Wireless Physical-layer ... - Jacobs University

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22 Chapter 3: Introduction to Graphs <strong>and</strong> <strong>Network</strong> <strong>Coding</strong><br />

coming out of C such that<br />

F (Q) =<br />

∑<br />

x ij −<br />

∑<br />

x ij . (3.8)<br />

(i,j)∈Q + (i,j)∈Q −<br />

Definition 3.11 Given lower <strong>and</strong> upper flow bounds b ij <strong>and</strong> c ij for each edge (i, j), the<br />

capacity C(Q) of a cut Q is<br />

∑<br />

C(Q) = c ij −<br />

∑<br />

b ij . (3.9)<br />

{j|(i,j)∈Q + } {j|(i,j)∈Q − }<br />

Definition 3.12 Q is said to be a saturated cut with respect to a set of flow if <strong>and</strong> only<br />

if F (Q) = C(Q).<br />

Using the Ford-Fulkerson algorithm, the first saturated cut that we find is called<br />

the minimum cut or min-cut representing the network bottleneck. This saturated cut is<br />

“minimum” in the sense that its flux is minimum among all possible saturated cuts. As<br />

suggested by intuition as well as the following max-flow/min-cut theorem, the capacity<br />

of the minimum cut equals the maximum flow of the network. The theorem is formally<br />

proved in [17].<br />

Theorem 3.1 Max-Flow/Min-Cut Theorem:<br />

(a) If x ∗ is an optimal solution of the max-flow problem, then the divergence out of S<br />

corresponding to x ∗ is equal to the minimum cut capacity over all cuts separating S from<br />

T .<br />

(b) If all lower arc flow bounds are zero, the max-flow problem has an optimal solution,<br />

<strong>and</strong> the maximal divergence out of S is equal to the minimum cut capacity over all cuts<br />

separating S from T .<br />

Figure 3.4 illustrates the max-flow/min-cut theorem. We can see from (b) that the<br />

capacity of the minimum cut is 5, equaling the maximum flow to T in (c).

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