11.03.2014 Views

Network Coding and Wireless Physical-layer ... - Jacobs University

Network Coding and Wireless Physical-layer ... - Jacobs University

Network Coding and Wireless Physical-layer ... - Jacobs University

SHOW MORE
SHOW LESS

Create successful ePaper yourself

Turn your PDF publications into a flip-book with our unique Google optimized e-Paper software.

Chapter 6: <strong>Wireless</strong> <strong>Physical</strong>-<strong>layer</strong> Secret-key Generation (WPSG) in Relay <strong>Network</strong>s:<br />

82<br />

Information Theoretic Limits, Key Extension, <strong>and</strong> Security Protocol<br />

14<br />

12<br />

between channel estimates<br />

between channel envelope estimates<br />

Mutual Information<br />

10<br />

8<br />

6<br />

4<br />

2<br />

0<br />

0 2 4 6 8 10 12 14 16 18 20<br />

SNR(dB)<br />

Figure 6.4: A simulation result showing the mutual information between the channel<br />

estimates of Alice <strong>and</strong> Bob, <strong>and</strong> between their channel envelope estimates<br />

is not easily derived when there are relays in between. For instance, if there is one relay<br />

in the path, as illustrated in Fig. 6.5, the channel parameter h a between the transmitter<br />

<strong>and</strong> the receiver becomes h aT = h a1 · h a2 , which is the product of two complex Gaussian<br />

r<strong>and</strong>om variables. If we let the real parts of h aT , h a1 , <strong>and</strong> h a2 be h aT r , h a1r , <strong>and</strong> h a2r ,<br />

respectively, <strong>and</strong> the imaginary parts be h aT i , h a1i , <strong>and</strong> h a2i , respectively, we have<br />

h aT i = h a1i h a2r + h a1r h a2i . (6.1)<br />

If we denote the r<strong>and</strong>om variables representing the r<strong>and</strong>om processes that generate<br />

h aT i , h a1i h a2r , <strong>and</strong> h a1r h a2i by Z, X, <strong>and</strong> Y respectively, the probability density function<br />

f Z (z) will be the convolution of f X (x) <strong>and</strong> f Y (y).<br />

f Z (z) =<br />

∫ ∞<br />

−∞<br />

f X (z − y)f Y (y)dy . (6.2)<br />

In our case, X <strong>and</strong> Y have the same probability density function<br />

f X (x) = f Y (x) = 4 K 0(4x)<br />

π<br />

, (6.3)

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!